PHYSICS MIDDLE SCHOOL

If you are driving 128.4 km/h along a straight road and you look down for 3.0s, how far do you travel during this inattentive period?

Answers

Answer 1

Answer:

Answer:

107 m

Explanation:

Convert km/h to m/s:

128.4 km/h × (1000 m / km) × (1 h / 3600 s) = 35.67 m/s

Distance = rate × time

d = 35.67 m/s × 3.0 s

d = 107 m

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1) There are many positive and negative aspects associated with nuclear power. Which is a negative aspect associated with nuclear power?

Answers

Nuclear power emits radiation.

What do you know about stars?

Answers

Blue stars are hotter than red stars

And the closest star to earth is our sun

A star's life begins with the gravitational collapse of a gaseous nebula, when a stars mass is greater that .4 times our sun expands to become a red giant.

A merry -go-round rotates at the rate of 0.4rev / s with an 78 kg man standing at a point 1.5 m from the axis of rotation. What is the new angular speed when the man walks to a point m from the center? Consider the merry-go-round is a solid 11 kg cylinder of radius of 1,5 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change in kinetic energy due to this movement ? Answer in units of

Answers

1) Final angular velocity is 5.22 rad/s

2) Change in kinetic energy: 639.8 J

Explanation:

In absence of external forces, the angular momentum of the merry-go-round must be conserved.

So we can write:

$L_1 = L_2\nI_1\omega_1 = I_2 \omega_2$

where

$I_1$ is the initial moment of inertia

$I_2$ is the final moment of inertia

$\omega_1$ is the initial angular velocity

$\omega_2$ is the final angular velocity

At the beginning, we have:

$\omega_1=0.4 rev/s \cdot 2\pi = 2.51 rad/s$

The moment of inertia is the sum of the moment of inertia of the cylinder + the moment of inertia of the man, therefore:

$I_1 = (1)/(2)MR^2+mr^2=(1)/(2)(11)(1.5)^2+(78)(1.5)^2=187.9 kgm^2$

The man later walks to a point 1 m from the centre, so the final moment of inertia is:

$I_2 = (1)/(2)MR^2+mr^2=(1)/(2)(11)(1.5)^2+(78)(1)^2=90.4 kgm^2$

Therefore, the final angular velocity is

$\omega_2 = (I_1 \omega_1)/(I_2)=((187.9)(2.51))/(90.4)=5.22 rad/s$

The angular velocity of the merry-go-round rotating is given by

$K=(1)/(2)I\omega^2$

In the first situation, we have

$I_1 = 187.9 kg m^2\n\omega=2.51 rad/s$

Therefore

$K_1 = (1)/(2)(187.9)(2.51)^2=591.8 J$

In the second situation, we have

$I_2= 90.4 kg m^2\n\omega_2=5.22 rad/s$

Therefore

$K_2=(1)/(2)(90.4)(5.22)^2=1231.6 J$

So the change in kinetic energy is

$\Delta K = K_2 - K_1 = 1231.6-591.8=639.8 J$

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

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As volume increases mass will__

Answers

If you're working with a solid or a liquid, the only way to increase volume
is to add more solid or liquid, so the mass must also increase.
(I don't want to get into temperature and confuse you.)

Not so with a gas. If you want to increase the volume of a jar of gas,
all you have to do is pipe it into a bigger jar. Gas always expands
to fill whatever you put it in. So if you're working with a gas, you can
increase the volume with no change in the mass.

I'm Pretty sure its B but I need to know as fast as possible which statement best describes universal law

a)it is in effect some of all time

b)it is in effect all the time

c)it changes over time

d)it operates under specific conditions

Answers

I agree, "B" is the correct answer
Hope it helps you :)

What describes a basic principle of nature that always occurs under certain conditions.

Answers

A basic principle of nature that always occurs under certain conditions is called a law. An example of that can be Newton's laws or the Laws of Thermodynamics since they are very famous laws in the world of science.

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