MATHEMATICS HIGH SCHOOL

A circular cylinder has a radius between 5.50 and 6.00 cm and a volume of 225 cm3. Write an inequality that represents the range of possible heights the cylinder can have to meet this criterion to the nearest hundrenth of the centimeter.

Answers

Answer 1
Answer:

Answer:

The answer is: 1.99<h<2.37

Step-by-step explanation:

The procedure is as followed

V=πr^2h

225=π(5.5)^2h

h=2.37

225=π(6)^2h

h=1.99

Related Questions

An umbrella that costs $6.00 to manufacture is sold for $11.70. What is the percent in price​
A 12 ounce bottle of shampoo last enrique 16 weeks.how lonh would you expect an 18 ounce bottle of the same brand to last him?
Please help with algebra 1) Mrs.Galicia sells online math and reading games. His revenue for each game (in dollars) is modeled by the given equations, where x is the number of days since the games went on sale.Math Game: M(d)=x^2-9x-10Reading Game: R(d)=2x+10Solve the system algebraically. After how many days is the revenue for each game the same? Show your work and explain your answer.
I know that y=20 and x=50 but will someone explain how to get them. Thanks!
Write 0.0003532 in scientific notation.a. 3.532 × 105 b. 3.532 × 10 4 c. 3.532 × 104 d. 3.532 × 10 5

7. (3 pt) What is the distance between points (−2, 8) and (6, −2)? Round to the nearest tenth of a unit.

Answers

The Exact answer is 12.80625, Rounded to the tenth is 12.8

Rewrite 5/2 as a mixed number.

Answers

it's 2 1/2 .... u should go on the math calculater!! it's called calculater soup or something

A scanner scanned 72 photos in 8 minutes. If it scans photos at a constant rate, it can scan photos in 23 minutes.

Answers

it can scan 207 photos in 23.

Please help I need to know now :(

Answers

Answer:

(6x*x^(3))/(y^(2))\n\n

Step-by-step explanation:

a^(-m)=(1)/(a^(m))\n\n(1)/(a^(-m))=a^(m)\n\na^(m)*a^(n)=a^(m+n)\n\n\n(6xy^(-2))/(x^(-3))=(6*x*x^(3))/(y^(2))\n\n=(6x^((1+3)))/(y^(2))\n\n=(6x^(4))/(y^(2))
I think it’s y^2.
...

4x-5=2(2x+1) find the x

Answers

First, do the distributive property: 4x-5=4x+2
This answer has no real solution. The term is no real numbers. 

Hi Brainiac


4x-5=2(2x+1)

Distribute

4x-5= (2)(2x)+(2)(1)

4x-5=4x+2

Subtract 4x

4x-5-4x= 4x+2-4x

-5=2

Add 5

-5+5=2+5

0=7

There are no solutions


I hope that's help:0

Math math math math + math equails wat?
3094857 x 7890 + 11x=

Answers

Answer:

24,418,421,851

Step-by-step explanation:

Answer:

24418421730+ 11x

Step-by-step explanation:
Other Questions
The following are angles in a convex quadrilateral: Angle A = 34 degrees Angle B = 108 degree Angle C = 65 degrees What is the measure of the missing angle?
One group of people purchased 10 hot dogs and 5 soft drinks for $35. Another group purchased 7 hot dogs and 4 soft drinks for $25.25. What is the cost of a single hot dog? A single soft drink?
❌❌EVALUATE SQUARE ROOTS❌❌1. Evaluate 6 + √14 + x - √9x when x = 2. a) 10 - 3√2 b) 10 - √2 c) 7 d) -4 2. Evaluate 6 + √14 + x - √9x when x = 2. (Write as decimal) a) 14.24 b) 7 c) 5.76 d) -4 Thank you !
Lamar is writing a coordinate proof to show that a segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas. He starts by assigning coordinates as given.A right triangle is graphed on a coordinate plane. The horizontal x-axis and y-axis are solid, and the grid is hidden. The vertices are labeled as M, K, and L. The vertex labeled as M lies on begin ordered pair 0 comma 0 end ordered pair. The vertex labeled as K lies on begin ordered pair 0 comma 2 b end ordered pair. The vertex labeled as L lies on begin ordered pair 2a comma 0 end ordered pair. A bisector is drawn from point M to the line KL. The intersection point on line KL is labeled as N. Enter the answers to complete the coordinate proof. N is the midpoint of KL¯¯¯¯¯KL¯ . Therefore, the coordinates of N are (a, ). To find the area of △KNM△KNM , the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM△KNM is . To find the area of △MNL△MNL , the length of the base ML is , and the length of the height is . So an expression for the area of △MNL△MNL is ab. Comparing the expressions for the areas shows that the areas of the triangles are equal.