A 0.8115 g sample of HCl was placed into a 50 mL volumetric flask and the sample was thoroughly dissolved in water to make 50 mL of solution. It required 22.07 mL of NaOH to reach the endpoint in the titration. What is the molarity of the NaOH solution?

Answers

Answer 1
Answer:

Answer:

Molarity of NaOH solution is 1.009 M

Explanation:

Molar mass of HCl is 36.46 g/mol

Number moles = (mass)/(molar mass)

So, 0.8115 g of HCl = (0.8115)/(36.46)moles HCl = 0.02226 moles HCl

1 mol of NaOH neutralizes 1 mol of HCl.

So, if molarity of NaOH solution is S(M) then moles of NaOH required to reach endpoint is (S* 22.07)/(1000)moles

So, (S* 22.07)/(1000)=0.02226

or, S = 1.009

So, molarity of NaOH solution is 1.009 M


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1) This method is a technique used in separating a less-dense substance from a denser one. A. Evaporation. B. Decantation. C. Picking. D. All of the above. 2) What will happen to the less-dense substance of mixtures if you separate them using decantation method? A. Remain the same. B. It will become solid. C. It will evaporate. D. It will float up. 3) In the process of decantation, the mixture is left: A. Behind. B. Undisturbed. C. Removed. D. None of the above. 4) How can the decantation method be useful in everyday life? A. It helps us to become more productive. B. It gives us satisfaction in our everyday living. C. It's just an ordinary technique. D. It helps us to make our everyday living more efficient and easier.

Answers

Answer:

1. B Decantation. 2. D 3. B

Explanation:

This method is often used when dealing with mixtures of liquids or immiscible liquids with different densities

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4. It's a handy method for separating substances based on their density For example, if you have a mixture of oil and water, you can use decantation to separate the two. By letting the mixture sit undisturbed, the oil, being less dense, will float to the top, allowing you to carefully pour it off and separate it from the water.

As atomic number increases within Group 15 on the Periodic Table, atomic radius(1) decreases, only
(2) increases, only
(3) decreases, then increases
(4) increases, then decreases

Answers

Answer is: (2) increases, only.

The atomic radius of a chemical element is a measure of the size of its atom.

The atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

Nitrogen (N), phosphorus (P), arsenic (As), antimony (Sb), bismuth (Bi) and moscovium (Mc) are in group 15 of Periodic table. They have same number of valence electrons (five).

Nitrogen has smallest atomic number and smallest atomic radius.

As atomic number increases within group 15, the atomic radius ; ( 2 )

  • Increases only

In the periodic table, the size of the atomic radius will continue to change as the the atomic number of the elements increase. Elements in the same group have the same/similar number of valence electron counts and also similar vacancy counts as well.

Therefore as  you go down the group, the atomic number of the elements in the same group increases and in response to that the distance between the nucleus and the outermost shell will also increase ( which is the atomic radius ).

Hence we can conclude that As atomic number increases within group 15,the atomic radius  Increases only .

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Which of the following is not a metal?
A) Ca
B) Se
C) Zn
D) Mn

Answers

B) Selenium is a nonmetal
Ca is not a metal so your answer is a.

Which of the following compounds is a gas at room temperature? A : CH3CH2OH B : CH3CH2CH2CH2CH2CH2CH3 C : CH3CH2CH3 D : HOCH2CH2OH

Answers

Answer:

C. CH_3CH_2CH_3

Explanation:

Molecules with the stronger intermolecular forces are pulled tightly together  to form solid at higher temperatures and that's why the freezing point is higher.

Also, molecules with the stronger intermolecular force have greater interaction between the molecules and thus on heating do not boil easily and have high boiling point also.

Thus, melting point and boiling point increases with increase in number of carbon atoms and also increase in intermolecular forces (like hydrogen bonding, if present).

Thus, the compound which is gas at room temperature is CH_3CH_2CH_3because it has least number of carbon atoms and absence of hydrogen bonding.

Final answer:

Among the choices, only CH3CH2CH3 (propane) is a gas at room temperature. The other compounds, CH3CH2OH (ethanol), CH3CH2CH2CH2CH2CH2CH3 (hexane), and HOCH2CH2OH (ethylene glycol) are all liquids.

Explanation:

Among the four compounds given, compound C, which is CH3CH2CH3 (also known as propane), is a gas at room temperature. Compound A (CH3CH2OH, or ethanol), compound B (CH3CH2CH2CH2CH2CH2CH3, or hexane), and compound D (HOCH2CH2OH, or ethylene glycol) are all liquids at room temperature.

The state of a compound at room temperature depends on factors like molecular mass and intermolecular forces. Propane has a smaller molecular mass and weaker intermolecular forces than the others, making it a gas at room temperature.

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How many mole ratios can be written for a chemical reaction involving 3 substances

Answers

Answer : 3 substance will have 3 mole ratios to be written for a chemical reaction.

Explanation : The mole ratio can be defined as ​the ratio between the amounts in moles of any two or more compounds involved in a chemical reaction.

It can be determined by comparing the coefficients the formulas of a balanced chemical equation. It is also known as the molar ratio or mole-to-mole ratio.

Hence, when 3 substances are involved in a chemical reaction 3 mole ratios can be written for it.

There can be three mole ratios that can be written involving three substances.It depends on the constant of your reactant to your product. It also depends on the asked mole ratio. But the maximum would be 3 mole ratios because you have 3 substances in your reaction.

Olive oil has a density of 0.92 g/mL. How much would 1 liter of olive oil weigh in grams?

Answers

Dimension analysis is to be used to solve this problem. First convert 1L to milliliters. That is equivalent to 1000 ml. Then by dimension analysis, multiply the volume ( 1000ml) to the density of oil (0.92 g/ml) resulting to the answer: 920 grams.