What is the end behavior of the graph of the polynomial function f(x) = 2x3 – 26x – 24?

Answers

Answer 1
Answer: The degree of the function is 3, so it's odd. The leading coefficient is 2, so it's positive. Therefore, the end behavior of the graph of the functions is:
as x approaches negative infinity, f(x) approaches negative infinity
as x approaches positive infinity, f(x) approaches positive infinity
Answer 2
Answer:

The end behavior of a polynomial function is the behavior of the graph of as approaches positive infinity or negative infinity. The degree and the leading coefficient of a polynomial function determine the end behavior of the graph.

Degree - 3 (odd);

Leading coefficient - 2 (positive).

Then

  • when x\rightarrow -\infty, then f(x)\rightarrow -\infty;
  • when x\rightarrow \infty, then f(x)\rightarrow \infty.

See attached graph of the function for graphical illustration.


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Answers

Already asked question.
But anyways, see the attachment i have added below.
I have it typed there

Quadrilateral QRST is a square. If TR = 50 and PT = 8x + 2, then find the value

Answers

x = 6

8(6) + 2 → 48 + 2

48 + 2 = 50

If the slope is 26.5° what is the rise per meter

Answers

Rise / run = tangent of the angle.

Tan(26.5) = 0.49858... , so the rise per meter is about 1/2 meter.

What does m and b stand for in y=mx+b?

Answers

B is where the line crosses the y axis
its called slope-intercept form. m is the slope where the lines cross and b is the y- coordinate of the y-intercept.

On a vertical line segment, point A is located at 50. Point B is located at 104. Point P is a point that divides segment AB in a ratio of 1:5 from A to B. Where is point P located?

Answers

Answer:

Step-by-step explanation:

Let the initial point on the line segment be O. If point A is located at 50 and point B is located at 104, then OA = 50 and OB = 104. Using the vector notation;

AO+OB = AB

(-OA)+OB = AB

-50+104 = AB

AB = 54

If point P divides the segment AB in a ratio 1:5, them AP:PB = 1:5

AP = 54/6

AP = 9

PB = 54-9

PB = 45

Hence the point P is located at 9 units from A and 45 units from B

Work each problem and connect the answers in order.1) 7 + -12 + −3
2) 2+ 8 + 7+-6
3) 13+12+12
11) -2- -6
12) -2--1
13) -15 - 4
14) 7-19
15) 5--20
6-18 + 16+ -12 + 5
16) -24 --2
7) 3.4 +2.7 +1.3+-1.2 17) −2+ -7 -1
8) + 7 + 7 + 7
3
9) -4-7
10) 2--5
17 +13 +13 +37
5) 24 +19+5 +3
21) -3 + 7 + 18
22) 14--3-4--1
23) 27-3+-24
24) (14--6)-(-5-13)
25) 10 - (5 +-7--2)
26) (-3--10) -[(5-8)+-10]
1
27) (-4--2) + (-16-5)
28) (27−−6) +-6
18) 7--13-12
19) -15--3-8 29) 27 - (-6 + −6)
20)-1-13 +-17 30) (16-4) - (8 +12)

Answers

Answers:

Sure, let's calculate the answers for each of the given problems:

1) \(7 + (-12) + (-3) = -8\)

2) \(2 + 8 + 7 + (-6) = 11\)

3) \(13 + 12 + 12 = 37\)

4) \(6 - 18 + 16 + (-12) + 5 = -3\)

5) \(24 + 19 + 5 + 3 = 51\)

6) \(-24 + 2 = -22\)

7) \(3.4 + 2.7 + 1.3 + (-1.2) = 6.2\)

8) \(7 + 7 + 7 = 21\)

9) \(-4 - 7 = -11\)

10) \(2 + 5 = 7\)

11) \(-2 + 6 = 4\)

12) \(-2 + 1 = -1\)

13 )\(-15 - 4 = -19\)

14) \(7 - 19 = -12\)

15) \(5 + 20 = 25\)

16) \(-24 + 2 = -22\)

17) \(-2 + (-7) - 1 = -10\)

18) \(7 + 13 - 12 = 8\)

19) \(-15 + 3 - 8 = -20\)

20) \(-1 - 13 + (-17) = -31\)

21) \(-3 + 7 + 18 = 22\)

22) \(14 + 3 - 4 + 1 = 14\)

23) \(27 - 3 + (-24) = 0\)

24) \((14 + 6) - (-5 - 13) = 38\)

25) \(10 - (5 + (-7) + 2) = 14\)

26) \((-3 + 10) - ((5 - 8) + (-10)) = 10\)

27) \((-4 + 2) + (-16 - 5) = -23\)

28) \((27 + 6) + (-6) = 27\)

29) \(27 - (-6 + (-6)) = 39\)

30) \((16 - 4) - (8 + 12) = -8\)

Now, connecting the answers in order:

-8, 11, 37, -3, 51, -22, 6.2, 21, -11, 7, 4, -1, -19, -12, 25, -22, -10, 8, -20, -31, 22, 14, 0, 38, 14, 10, -23, 27, 39, -8.