What is 12 percent of 120?

Answers

Answer 1
Answer: 12% of 120 is 14.4

Change the percentage into a decimal by dividing over 100:

12 / 100 = 0.12

Multiply:

0.12 × 120 = 14.4
Answer 2
Answer:

Answer:

12\% \: of \: 120 \n (12)/(100) * 120 \n (1440)/(100) \n \boxed{14.4}


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How many sides does a regular polygon have that has an angle of 20
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Which expression represents 100 divided by an unknown number?A. 100 • p B. 100 ÷ p C. 100 – p D. 100 + p

The diagram shows two parallel lines a andb cut by transversal lines.
Part A
What is an equation that can be used to
solve for x?
Part B
What is the value of x?

Answers

Answer:

y = 180 - (36 + 65)

x = 69

Step-by-step explanation:

Final answer:

To solve for x in the given diagram of parallel lines cut by a transversal, use the concept of corresponding angles. The value of x is 60°.

Explanation:

Part A: To solve for x, we can use the corresponding angles formed by the transversal and the parallel lines. One of the corresponding angles is x + 60°. Since the other corresponding angle is 120°, we can set up the equation x + 60° = 120°. Solving for x, we find that x = 60°.

Part B: The value of x is 60°.

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5x + 3 = x + 11
Please help fast thankyou

Answers

Answer:

x = 2

Step-by-step explanation:

5x + 3= x + 11

5x - x = 11 - 3

4x = 8

x = 2

Helpppppppp
Write a linear function f(x) with the values f(3) = -1 and f(6) = 1.

Answers

The Answers hope this helps

Which point on the number line represents 0.059?

Answers

It is in the thousandths place

Final answer:

The point on the number line that represents 0.059 is very close to 0. Specifically, it is located a bit over halfway along the sixth segment of the section between 0 and 1, if this section is divided into 100 equal segments.

Explanation:

The point on the number line that represents 0.059 would be very close to 0. On a number line, which sequences numbers from left to right in increasing order, the number 0.059 is more than 0 but less than 1, so it appears somewhere between these two points. However, because 0.059 is substantially less than 1, its exact position would be much nearer to the 0 mark than the 1.

For example, if we consider a number line stretching from 0 to 1 and divide it into 100 equal segments, each representing 0.01, the point 0.059 would be located just a little over halfway along the sixth segment from the 0 point. This is because the decimal 0.059 rounds to 0.06, which is specifically represented by the position at the end of the sixth segment.

This process allows us to graphically represent decimals on the number line, and provides context for understanding the size and relative value of this decimal number.

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Beth has 250 comic books in her collection She begins to sell 20 of them each week. Martin has 80 comic books in his collection. Hebegins buying 15 new comic books each week
Select from the choices below, dragging and dropping to build an inequality that could be used to determine when Martin's comic book
collection exceeds Beth's

Answers

Answer:

The answer to your question is  250 - 20 < 80 + 15x

Step-by-step explanation:

Data

Beth  has 250 books and sells 20 each week

Martin has 80 books and sells 15 each week

week = x

Process

1.- Write an equation for each situation

Beth         250 - 20x            

Martin       80 + 15 x

2.- Write the inequality

                   250 - 20 < 80 + 15x

C(squared)L(squared) + 100v(squared) = 100c(squared)
I have to solve for L

Answers

first subtract 100v² from both sides to get:

C²L²=100c²-100v²

Then divide both sides by C²:

L²=(100c²-100v²)/C²

Then take the square root of both sides:

L=+ or - the square root of (100c²-100v²)/C²

Answer:

L = ±√( (100c² - 100v²) / C² )

Step-by-step explanation:

You're just doing reverse PEMDAS.

So first get all the values correlated with L on one side and the non-L values on the other side using subtraction/addition.

Then remove all coefficient using multiplication/division.

Then take the sqareroot to get rid of the squre on the v.

Remember that taking squareroot gives a ± answer because

(x)² = (-x)²