Which test point holds true for 2/5x - 1/5>=0 ?

Answers

Answer 1

Answer: 2/5x >= 1/5 multiple both sides by 5/2
so , x >= 1/2

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The point at which a company's profits equal zero is called the company's break-even point. let R represent a company's revenue, let C represent the company's costs, and let x represent the number of units produced and sold each day.R(x)=12x
C(x)=6.5x+22000
a) Find the firm's break-even point; that is, find x so that R=C
b) Find the values of x such that R(x)>C(x). this represents the number of units that the company must sell to earn a profit.

Answers

R ( x ) = 12 x ( revenue )
C ( x ) = 6.5 x + 22,000 ( cost )
a ) Break-even point : R ( x ) = C ( x )
12 x = 6.5 x + 22,000
12 x - 6.5 x = 22,000
5.5 x = 22,000
x = 22,000 : 5.5
x = 4,000
b ) R ( x ) > C ( x )
x > 4,000
The number of units that the company must sell to earn a profit is 4,001 or more.

a) R=C implies 12x=6.5x + 22000, and then 12x - 6.5x= 22000, 5.5x= 22000, from where we find x = 22000 : 5.5, x=4000.

b) For R(x)>C(x), we get 12x>6.5x + 22000, which implies after the same calculation, x>4000

Find the sum 1/5+3/8

Answers

The answer to your question is 23/40.

1/5 + 3/8

= 1/5 * 1 + 3/8 * 1

= 1/5 * 8/8 + 3/8 * 5/5

= 8/40 + 15/40

= 23/40

Use cross multiplication to solve the following proportion. 1. /6 = 15/18

Answers

Answer:

x=5

Step-by-step explanation:

x/6=15/18

18x=6 times 15

18x=90/18

x=5

What is the slope equation? Drag and drop answers

Answers

Answer:

y = 2x + 9

Step-by-step explanation:

The y-intercept:9

Slope:2x

5xthe power of x...................

Answers

Answer:

$5x^(x)$

Let point L be between M and N on MN. Given that MN=31, ML= h-15 and LN = 2h-8. Find LN

Answers

Since point L is merely found on the line MN, ML and LN are considered to be line segments. So adding both line segments should add up to line MN's total length which is 31 units. We can use the given relations to create a mathematical equation as follows:

Given: MN = 31; ML = h - 15; LN = 2h - 8

MN = ML + LN

Substituting the given values:
31 = h - 15 + 2h - 8
31 = 3h - 23

It is necessary to solve for the value of h. To do this, we must isolate h and solve for it:

Adding 23 to both sides of the equation:
31 + 23 = 3h - 23 + 23
54 = 3h
h = 18

Substituting the value of h to the equation of LN we get the following:
LN = 2(18) - 8
LN = 36 - 8
LN = 28

Therefore the value of LN is 28.

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