A study has shown that 75% of teenage boys drink 34 oz of soda per day. How many 12 oz cans of soda would a boy drink in a week if he drank 34 oz per day.

Answers

Answer 1
Answer: he would drink 19 bottles and 0.833 oz..... Hope its right!

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Ing page.
1. y = 3x
y = x + 4

Answers

Answer:

Step-by-step explanation y=2x

PLZPLZ PLZ PLZ PLZ PLZ HELP ME I AM CONFUSED ND DONT KNOW WHAT TO DO!!

Answers

The answer to your question is 2

Answer:

lol i think its 0.5 because you follow the lin and it goes up each time hope this hlps

Step-by-step explanation:

Please help with this question and explain it. :) ty in advance.

Answers

So first we add the total pounds of harvested crop by the total number of hours:
48/24 which is 2
So 2 pounds of crop is harvested every hour, assuming that the working is constant throughout all four workers. 
So:
Employee - 
A: 12 pounds
B: 8 pounds
C: 12 pounds
D: 16 pounds

Calculate: 2.7·6.2–9.3·1.2+6.2·9.3–1.2·2.7
not pemdas. some shortcut method plz

Answers

Answer:

60

See steps

Step by Step Solution:

More Icon

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "2.7" was replaced by "(27/10)". 8 more similar replacement(s)

STEP

1

:

          27

Simplify   ——

          10

Equation at the end of step

1

:

   27 62   93 12    62 93    12 27

(((——•——)-(——•——))+(——•——))-(——•——)

   10 10   10 10    10 10    10 10

STEP

2

:

          6

Simplify   —

          5

Equation at the end of step

2

:

   27 62   93 12    62 93    6 27

(((——•——)-(——•——))+(——•——))-(—•——)

   10 10   10 10    10 10    5 10

STEP

3

:

          93

Simplify   ——

          10

Equation at the end of step

3

:

   27 62   93 12    62 93   81

(((——•——)-(——•——))+(——•——))-——

   10 10   10 10    10 10   25

STEP

4

:

          31

Simplify   ——

          5

Equation at the end of step

4

:

   27 62   93 12    31 93   81

(((——•——)-(——•——))+(——•——))-——

   10 10   10 10    5  10   25

STEP

5

:

          6

Simplify   —

          5

Equation at the end of step

5

:

   27 62   93 6   2883  81

(((——•——)-(——•—))+————)-——

   10 10   10 5    50   25

STEP

6

:

          93

Simplify   ——

          10

Equation at the end of step

6

:

   27 62   93 6   2883  81

(((——•——)-(——•—))+————)-——

   10 10   10 5    50   25

STEP

7

:

          31

Simplify   ——

          5

Equation at the end of step

7

:

   27   31     279     2883     81

(((—— • ——) -  ———) +  ————) -  ——

   10   5      25       50      25

STEP

8

:

          27

Simplify   ——

          10

Equation at the end of step

8

:

   27   31     279     2883     81

(((—— • ——) -  ———) +  ————) -  ——

   10   5      25       50      25

STEP

9

:

Calculating the Least Common Multiple

9.1    Find the Least Common Multiple

    The left denominator is :       50

    The right denominator is :       25

      Number of times each prime factor

      appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 1 0 1

5 2 2 2

Product of all

Prime Factors  50 25 50

    Least Common Multiple:

    50

Calculating Multipliers :

9.2    Calculate multipliers for the two fractions

  Denote the Least Common Multiple by  L.C.M

  Denote the Left Multiplier by  Left_M

  Denote the Right Multiplier by  Right_M

  Denote the Left Deniminator by  L_Deno

  Denote the Right Multiplier by  R_Deno

 Left_M = L.C.M / L_Deno = 1

 Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

9.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

 L. Mult. • L. Num.      837

 ——————————————————  =   ———

       L.C.M             50

 R. Mult. • R. Num.      279 • 2

 ——————————————————  =   ———————

       L.C.M               50  

Adding fractions that have a common denominator :

9.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

837 - (279 • 2)     279

———————————————  =  ———

     50            50

Equation at the end of step

9

:

 279    2883     81

(——— +  ————) -  ——

 50      50      25

STEP

10

:

Adding fractions which have a common denominator

10.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

279 + 2883     1581

——————————  =  ————

   50          25

Equation at the end of step

10

:

1581    81

———— -  ——

25     25

STEP

11

:

Adding fractions which have a common denominator

11.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

1581 - (81)     60

———————————  =  ——

   25          1

Final result :

60

Answer:

2222222222

Step-by-step explanation:

5550 divided by 10 to the third power

Answers

Answer: 5.55

Step-by-step explanation:

5550/10^3

10 * 10 * 10 = 1,000

5550/1000 = 5.55

Answer:

5.55

Step-by-step explanation:

10*10=100

100*10=1000

5550/1000=

5.55

HELP it's a maths question worth 4 marks

Answers

a = 3, b= - 4 and c = - 4

expand the left side using FOIL

(2x + 1)(ax + b) = 2ax² + 2bx + ax + b = 2ax² + x(2b + a) + b

compare the coefficients of expressions on left and right sides.

compare 2ax² + x(2b +a) + b with 6x² - 5x + c

coefficients of x² terms → 2a = 6 ⇒ a = 3

coefficients of x terms → 2b + a = - 5 → 2b + 3 = - 5 → 2b = - 8 ⇒ b = - 4

constant terms c = b = - 4