The bill for lunch was 24.50 mr smith add a 20% tip how much did mr smith pay

Answers

Answer 1
Answer:

Answer:

Mr.Smith paid $29.4.

Step-by-step explanation:

Mr.Smith paid $24.5 plus additional 20% of $24.5, and to figure out the total amount that he paid, we need to know what is 20% of $24.50.

20% of $24.50 is:

(20)/(100)*24.5=0.2*24.6=4.9.

Mr.Smith paid additional $4.9; therefore, the total amount he paid was

$24.5 + $4.9 = $29.4.

Mr. smith paid $29.4.


Related Questions

What is X divided by 2?
4 x (22+5)Simplify the expression.
Given that RT ≅ WX, which statement must be true?RT + TW = WX + TW RT = 2(RX)WX = 2(RX)RT + TW = RX
What is the vertex form of a parabola with vertex at the origin and the focus at (0,1/8)?
The length of a text messaging conversation is normally distributed with a mean of 2 minutes and a standard deviation of .5 minutes. What is the probability that a conversation lasts longer than 3 minutes?0.043351 0.063748 0.02275 0.095424

Which statement is true?

Answers

Answer:

Two shapes have corresponding congruent parts if and only if the shapes are congruent and one shape can be mapped to the other using a series of rigid transformations. (The first option)

Step-by-step explanation:

The other three statements are false.

Two shapes can have corresponding congruent parts without being congruent. For example, a square and a rectangle can have congruent sides, but they are not congruent shapes.

Two shapes can be congruent without being able to be mapped to each other using a series of rigid transformations. For example, a sphere and a cube are congruent shapes, but they cannot be mapped to each other using only rigid transformations.

Two shapes can be non-congruent and be able to be mapped to each other using a series of rigid transformations. For example, a square and a rectangle can be mapped to each other using a combination of a rotation and a translation.

7/8(-4/5)= the answer to this question

Answers

(7)/(8) * (-4)/(5)
let's simplify the terms now 
so, we are let with 

(7)/(2) * (-1)/(5)
Now lets multiply them together

(-7)/(10)

hope this helped... :)

Consider the type of equations 5x+y=31
-3x+4y=37
solve the first equation as y in terms of x
like y=.....

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You just have to isolate the y term for both equations so the first one would be y=31-5x because you have to subtract x from both sides.

The second one would be y=3+3x and all of that over 4 because to get the y isolated, you have to add 3x to both sides and then divide by 4 to get 4 y to just be y.

16/8 into a mixed number

Answers

ok well the answer will be 2 because 8+8=16 and 8 can go into 16 2 times.
the answer is 
2/1 
because 8 times 2 is 16 and if  you divide 16 by 8 u will get 2 and 8 divided by 8 is 1

Select all statements that are true about the linear equation.y=4x−3

The graph of the equation is a single point, representing one solution to the equation.

The point (1, 1) is on the graph of the equation.

4x−y=−3 has the same graph.

Since the point (0, −3) is a solution to the equation, it is on the graph of the equation.

The graph of the equation is the set of all points that are solutions to the equation.

Answers

The correct answer for this question would be:

"The graph of the equation is the set of all points that are solutions to the equation."

"The point (1, 1) is on the graph of the equation."

And "The point (0, -3) is on the graph of the equation."

- I just took the test.

For point (1, 1): 1 = 4(1) - 3 = 4 - 3 = 1.
Therefore, the point (1, 1) is on the graph of the equation.

Since the point (0, −3) is a solution to the equation, it is on the graph of the equation.

The graph of the equation is the set of all points that are solutions to the equation.

Which of the solution sets is all real numbers?
|x| < -1
|x| = -1
|x| > -1

Answers

Answer:

The solution sets is all real numbers in case of:

                        |x| > -1

Step-by-step explanation:

We know that modulus is a function with the property such that:

                      if a<0 then |a|= -a

that is the modulus of a negative number is positive and if a≥0

                                then |a| =a

and modulus of a positive value is also positive.

i.e. modulus function always gives positive value.

Hence,

1)

|x|<-1

This is not possible as modulus function always gives a value ≥0 for all real numbers.

2)

|x|= -1

This is also not possible as modulus of any number can't be negative.

3)

|x| > -1

The modulus of any number will definitely be greater than or equal to zero.

    Hence, the solution set contain all the real numbers.

The last one is all real number