Two cards are drawn in succession from a pack of 52 well-shuffled cards. find the probability that :1) only the first card is a king
2) first card is a jack of diamonds or a queen 3) at least one card is a picture card
4)not more than one card is a picture card
5) the cards and not of the same suit
6) the second card is not a heart
7) the second card is not a heart given that the first card is a heart
8) the cards are Aces or diamond or boats

Answers

Answer 1

Answer: Probabilities:
1) 4/52 * 48/51 = 192/2652 = 16/221
( explanation : 4- the number of kings, 52- the number of all cards on the pack, 48 - the number of other cards, 51- the number of cards that remain after picking first card)
2) (1/52+4/52) * 51/51 = 5/52 * 1 = 5/52
( in brackets are probabilities that 1st card is jack diamond or a queen )
3) 12/52 * 11/51 + 12/52 * 40/51 + 40/52 * 12/51= 91/221
( first is the probability that there are no picture cards, then one picture card: probability 12/52 * 40/51 that 1st is picture card and 40/51 * 12/52 that 2nd is a picture card)
4) 40/52 *39/51 + 12/52 *40/51 + 40/52 * 12/51= 210/221
5) 13/52 * 39/51= 169/884
( first is one suit and 2nd is another)
6) 39/52 * 38/51 + 13/52 + 39/51= 19/34
7)13/52 * 39/51 = 13/68
8) 4/52 * 3/51 + 13/52 * 12/51 + 4/52 * 12/51 + 1/51 =29/663

60 milligrams is the right dosage for the child.

Step-by-step explanation:

The given expression is

$C=(a)/((a+12)) * 180$

Where $a=6$ , because according to the problem, the child is 6 years old.

Replacing and solving, we have

$C=(6)/((6+12) )* 180=(6)/(18 )* 180=60mg$

Therefore, if the adult dosage is 180 milligrams, and the child is 6 years old, the right dosage is 60 milligrams.

c+ childs dosage in miligrams

Which of these is a simplified form of the equation 9p + 3 = − p + 7 + 2p + 3p?5p = 4

15p = 10

9 = 4

12 = 13

Answers

Answer:

Option (a) is correct.

5p = 4

Step-by-step explanation:

Given : equation 9p + 3 = − p + 7 + 2p + 3p

We have to simplify the given equation 9p + 3 = − p + 7 + 2p + 3p.

Consider the given equation 9p + 3 = − p + 7 + 2p + 3p

Like terms are terms having same variable with same power.

Adding like terms, we get,

9p + 3 = 7 + 4p

Subtract 4p both isde, we have,

9p - 4p + 3 = 7 + 4p -4p

Simplify, we get,

5p + 3 = 7

Subtratc 3 both isde, we have,

5p = 4

Thus, option (a) is correct.

Move all the p's to one side and the number to the other side: 9p + p - 2p - 3p = 7 - 3 5p = 4

If 35% of a number is 150, find 15% if the number

Answers

Answer:

64 2/7

Step-by-step explanation:

0.35x = 150

x = 3000/7

0.15(3000/7) = 450/7 = 64 2/7

Let P(x) = F(x)G(x) and Q(x) = F(x)/G(x), where F and G are the functions whose graphs are shown.(a) Find P '(2). (b) Find Q'(7).

Answers

Hello,

Very nice like question!

a)
F(2)=3 ; G(2)=2
F'(2)=0; G'(2)=1/2
P'(x)=F'(x)*G(x)+F(x)*G'(x)

P'(2)=0*2+3*1/2=3/2

b)
F(7)=5; G(7)=1
F'(7)=1/4; G'(7)=-2/3

Q'(x)=(F'(x)*G(x)-F(x)*G'(x)) / G²(x)

Q'(7)=(1/4*1-5*(-2/3))/1²=1/4+5/3=23/12

Convert 324 centimeters to meters.

3.24 m
32.4 m
3,240 m
3,240 m

Answers

To convert from meters to centimeter you divide by 100
: . 324 cm to m = $(324cm)/(100) =<span> 3.24m</span>$

thus A

If M(x, y) is the midpoint of AB with A(3, 5) and B(-4, 8), then which Quadrant is M located in? (Points : 1) Quadrant I Quadrant II Quadrant III Quadrant IV Question 2. 2. Given A(9, 11), B(3, -4), C(6, -9), and D(-7, 7), then the midpoint of which line located in Quadrant II? (Points : 1) AB BC AC BD Question 3. 3. Given A(6, -17), B(-6, 17), C(4, 9), D(-4, 4), the midpoint of which segment is at the origin? (Points : 1) AB BC AC AD

Answers

M is located in Quadrant II, the line BD has a midpoint located in Quadrant II, AD has a midpoint at the origin.

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