MATHEMATICS HIGH SCHOOL

What is the equation of the line perpendicular to 2x − 5y = −35 that contains the point (10, 4)?

Answers

Answer 1
Answer: perpendicular has slope that multiplies to -1 in other sloope

thsi one

2x-5y=-35
-5y=-2x-35
y=2/5x+7
slope=2/5
2/5 times -5/2=-1
y=-5/2x+b
findn b
(10,4)
(x,y)
4=-5/2(10)+b
4=-25+b
21=b
y=-5/2x+21
2y=-5x+42
5x+2y=42
Answer 2
Answer: I left the equation in the gradient-intercept form which is just the form where the 'y' variable in the equation is with a coefficient of 1.... Hope you can see the picture though.

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Help quick!If X= -3
What is:

2
X + X =

( what is X cubed add X)

Answers

i thought that was all one equation lol this is very simple just plug in -3 for x 
which is -3^2-3 which is -12 

Answer:

-12

Step-by-step explanation:

(a) Solve 7( k - 3 ) = 3k - 5 (b) Expand and simplify (2x + 3 )( x - 8)

(c) Solve 7 - 3 f  = 2
                 4

Answers

a) 7(k-3)=3k-5\n 7k-21=3k-5\n 7k-3k=-5+21\n 4k=16\n k=\frac { 16 }{ 4 } \n k=4

b) (2x+3)(x-8)\n 2{ x }^( 2 )-16x+3x-24\n 2{ x }^( 2 )-13x-24

c) \frac { 7-3f }{ 4 } =2\n 7-3f=4\cdot 2\n 7-3f=8\n -3f=8-7\n -3f=1\n f=-\frac { 1 }{ 3 }
(a)\n7(k-3)=3k-5\n7(k)+7(-3)=3k-5\n7k-21=3k-5\ \ \ \ |add\ 21\ to\ both\ sides\n7k=3k+16\ \ \ \ |subtract\ 3k\ from\ both\ sides\n4k=16\ \ \ \ \ |divide\ both\ sides\ by\ 4\n\boxed{k=4}


(b)\n(2x+3)(x-8)=(2x)(x)+(2x)(-8)+(3)(x)+3(-8)\n\n=2x^2-16x+3x-24=\boxed{2x^2-13x-24}


(c)\n(7-3f)/(4)=2\ \ \ \ |multiply\ both\ sides\ by\ 4\n\n\not4^1\cdot(7-3f)/(\not4_1)=4\cdot2\n\n7-3f=8\ \ \ \ \ |subtract\ 7\ from\ both\ sides\n\n-3f=1\ \ \ \ \ |divide\ both\ sides\ by\ (-3)\n\n\boxed{f=-(1)/(3)}

Abcd is a rectangle. Find the length of each diagonal. .AC= 3y/5 BD=3y-4

Answers

Answer:

AC = BD = 1 unit

Step-by-step explanation:

 Given : length of diagonal of rectangle ABCD  AC=(3y)/(5) and BD=3y-4

We have to find the length of diagonal.

We know In rectangle diagonal are of equal lengths.

Therefore, for rectangle ABCD diagonals AC= BD

Substitute the values, we get,

(3y)/(5)=3y-4

Cross multiply , we get

3y=5(3y-4)

On simplyfy , we get

3y=15y-20

Solve for y , we get

15y-3y=20

12y=20

Divide both side by 12, we get,

y=(20)/(12)=(10)/(6)

Thus, put the values of y in AC and BD to find the length of diagonals , we get,

AC=(3y)/(5)=(3)/(5)*(10)/(6)=1

Similarly for BC, we get,

BD=3y-4=3((10)/(6))-4=5-4=1

Thus, AC = BD = 1 unit
I hope this helps you

What is the slope between 3,6 and 11,6

Answers

Answer:

slope = 0

Step-by-step explanation:

calculate the slope m using the slope formula

m = (y_(2)-y_(1) )/(x_(2)-x_(1) )

let (x₁, y₁ ) = (3, 6 ) and (x₂, y₂ ) = (11, 6 )

substitute these values into the formula for m

m = (6-6)/(11-3) = (0)/(8) = 0

(Helpppp)Write slope-intercept form of the line which is perpendicular bisector toa segment with endpoints A(5,9), B(7,13).

Answers

Answer:

the slope-intercept form of the line which is perpendicular bisector to the segment with endpoints A(5,9), B(7,13) is y = (-1/2)x + 14

3x - 17 = 46 . solve for x

Answers

Answer:

x = 21

Step-by-step explanation:

We can simplify this equation down until we have x isolated.

3x - 17 = 46

If we add 17 to both sides:

3x = 63

Now we can divide both sides by 3:

x = 21

So x = 21.

Hope this helped!
Answer:
x= 21

Explaination:
3x - 17 = 46
3x = 46 + 17
3x = 63
3x/3 = 63/3
x = 21
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