Which measurement is most accurate to describe the distance from Los Angeles to New York City?8,000 mm
6,000 m
50 km
4,000 km

Answers

Answer 1
Answer: mm = millimeters
m = meters
km = kilometers

So the distance is roughly 2, 500 miles so 4000km would be closer than the 3 measurements.
Answer 2
Answer:

Answer: it will be  4,000 km

Step-by-step explanation:


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What is half of a quarter of 400?

Answers


A quarter is 100 and half of that is 50
so what is 1/2 times 1/4 times 400 or
what is 1/8 of 400
the answer is 50

determine whether the following is valid or invalid: it's easy enough to do logic if you think logically. fortunately, i have no trouble doing logic, so i guess i think logically.

Answers

Answer:

Clearly it is invalid, as the converse of the statement "If one thinks logically, then it's easy to do logic." is being described.

Compare partial products and regrouping how the methods are alike and different

Answers

Answer:

We get the same answer from both processes.In the end, it is a multiplication process. In partial product we take the values of ones, tens, hundreds in each step and then add them together. In regrouping same thing happens but we do not break them down to processes.

Step-by-step explanation:

In Partial products we multiply the numbers partially and add them together to get the answer. It is easier to explain with an example, lets say we multiply 47 by 3


1) 47

  ×3

--------

  21


2) 47

   ×3

---------

   21

 120 ((3*40)

3) 3 8

    ×3

----------

  +21

  120

-----------

   141

In Regrouping we add the partial products to the next tens,hundreds and so on. We don not write them down and then add later. Lets take the same example and do the multiplication with Regrouping method.


1)2 --------> (3*7=21 write the number in tenth place here)

 47

 ×3

 ___

 __1  --------> (3*7=21 write the number in ones place here)


2)47

  ×3

 ___

 141   (3*4=12 then add the 2 above to get 14)

We get the same answer from both processes.In the end, it is a multiplication process. In partial product we take the values of ones, tens, hundreds in each step and then add them together. In regrouping same thing happens but we do not break them down to processes.

Partial products are different in regrouping in terms of how numbers are clustered from a set equation as a whole delivering it individual but naturally to all the numbers involved in the set. 
Regrouping is just like the commutative or associative property of numbers.
Associative property of addition is used when you want to group addends. This is mainly used to cluster set of numbers or in this case, addends. How do you use the associative property when you break apart addends? Simple you group them using the open and closed parentheses or brackets. Take for an example 1 + 1 + 2 = 4. Using the associative property you can have either (1 + 1) + 2 = 4 or 1 + (1 + 2) = 4 clustered into place.  

If you expand and simplify (2x+3)(x+4)

Answers

Answer:

The answer is 2x² + 11x + 12.

Step-by-step explanation:

You have apply Distributive Law,

a(m + n) = am + an

So for this question :

(2x + 3)(x + 4)

= 2x(x) + 2x(4) + 3(x) + 3(4)

= 2 {x}^(2)  + 8x + 3x + 12

= 2 {x}^(2)  + 11x + 12

(2x + 3)(x + 4) \n  = 2x(x + 4) + 3(x + 4) \n  = 2x * x + 2x * 4 + 3 * x + 3 * 4 \n  =  {2x}^(2)  + 8x + 3x + 12 \n  =  {2x}^(2)  + 11x + 12 \n hope \: it \: helps

Algebra II. Radical expressions.: Multiply, and then simplify if possible. Show your work.

Answers

remember distributive property
a(b+c)=ab+ac
a(b-c)=ab-ac


also
law of exponents
√(mn)=√(n) √(m)

and
(a-b)(a+b)=a^2-b^2 (for question 14)
and (a+b)^2=a^2+2ab+b^2 (for question 15)




11.  √(2x)(√(6x)-3√(x))=\sqrt{12x^(2)}-3\sqrt{2x^(2)}=2x√(3)-3x√(2)

12. 108+(28∛21)

13. (-2√6)+(4√10)

14.√(2x-3)-49

15. 2x+(20√x)+50

16. (3∛2)-(6∛4)-16

17. 42x-6

Find the greatest common factor.
2y^3, 8y

Answers

Answer:

STEP1:Equation at the end of step 1

2y3 - 8y

STEP2:

STEP3:Pulling out like terms

 3.1     Pull out like factors :

   2y3 - 8y  =   2y • (y2 - 4) 

Trying to factor as a Difference of Squares:

 3.2      Factoring:  y2 - 4 

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

         A2 - AB + BA - B2 =

         A2 - AB + AB - B2 =

         A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 4 is the square of 2

Check :  y2  is the square of  y1 

Factorization is :       (y + 2)  •  (y - 2) 

Final result :

2y • (y + 2) • (y - 2)