What is the median for the set of data?
6,7,10,12,12,13

Answers

Answer 1

Answer:

The median for this set of data is 11.

Work is provided in the image attached.

Answer 2

Answer: the median is 11 because to find the median you rank the numbers from least the greatest, but in this case there are two middle numbers 10 & 12, so to get the median you add 10+12=22 which equals 22 the divide it by 2 which now makes it 11. and that's you answer

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At a competition 24 of 40 members of a middle school band won a metal. What percentage of the members of the band won a medal

Answers

The percentage of the members of the band won a medal is 60%.

Given that, at a competition 24 of 40 members of a middle school band won a metal.

What is percentage?

Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".

The fraction for 24 of 40 members is

24/40

So, the percentage

= 24/40 ×100

= 60%

Hence, the percentage of the members of the band won a medal is 60%.

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Answer:

Step-by-step explanation:

24/40=60%

How do you find the surface area of a regular pyramid

Answers

The surface area of the pyramid is calculated by the formula B +(1/2) *P*L.

What is a Regular Pyramid?

A regular pyramid is a three dimensional structure with a regular polygon base and all the lateral surfaces are equal.

The surface area of a Regular Pyramid is the sum of the area of the base and the area of the lateral surface.

Surface area of Pyramid = Area of base + Lateral surface area of the sides

Surface area of Regular Pyramid = B +(1/2) *P*L

Here P is the perimeter of the base and L is the slant height, B is the area of the base.

Therefore, the surface area of the pyramid is calculated by the formula B +(1/2) *P*L.

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The lateral surface area of a regular pyramid is the sum of the areas of its lateral faces. The total surface area of a regular pyramid is the sum of the areas of its lateral faces and its base. The general formula for the lateral surface area of a regular pyramid is where p represents the perimeter of the base and l the slant height. Example 1:Find the lateral surface area of a regular pyramid with a triangular base if each edge of the base measures 8 inches and the slant height is 5 inches.The perimeter of the base is the sum of the sides.p = 3(8) = 24 inchesThe general formula for the total surface area of a regular pyramid is where p represents the perimeter of the base, l the slant height and B the area of the base. Example 2:Find the total surface area of a regular pyramid with a square base if each edge of the base measures 16 inches, the slant height of a side is 17 inches and the altitude is 15 inches.The perimeter of the base is 4s since it is a square.p = 4(16) = 64 inches The area of the base is s2.B = 162 = 256 inches2T. S. A. = There is no formula for a surface area of a non-regular pyramid since slant height is not defined. To find the area, find the area of each face and the area of the base and add them.

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Find dy/dx
2x+3y=sinx

Answers

$2x+3y=sinx\n\n3y=sinx-2x\ \ \ \ /:3\n\ny=(1)/(3)(sinx-2x)\n\n(\delta y)/(\delta x)=\left[(1)/(3)(sinx-2x)\right]'=(1)/(3)\left[(sinx)'-(2x)'\right]=(1)/(3)(cosx-2)$

What is the distance between point A and point B? Round to nearest tenth.

Answers

Answer:

$d \approx 12.6$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra II

Distance Formula: $d = √((x_2-x_1)^2+(y_2-y_1)^2)$

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point A (-4, 2)

Point B (8, 6)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d.

Substitute [DF]: $d = √((8+4)^2+(6-2)^2)$
Add/Subtract: $d = √((12)^2+(4)^2)$
Exponents: $d = √(144+16)$
Add: $d = √(160)$
Simplify: $d = 4√(10)$
Evaluate: $d = 12.6491$
Round: $d \approx 12.6$

What is the domain (in interval notation) of the following functions?1. g(x)=3/(5x-4)
2. h(x)=√(x)/(x-5)
3. f(x)=√(x)/(x^2-5x)
4. g(x)=(√(x)+5)/(x^2-x-20)
5. h(x)=3/(x^2+1)
6. f(x)=(√(x-2))/(x+1)
7. g(x)= x^2/(3x^2-x-2
8. h(x)=3(x-4)^2-7
Number sets in parenthesis are either on top of or beneath the fraction bar and ^2 here represents a number squared.

Answers

$1.\ng(x)=(3)/(5x-4)\n\nD:5x-4\neq0\to5x\neq4\ \ \ /:5\to x\neq(4)/(5)\to x\in\mathbb{R}\ \backslash\ \{(4)/(5)\}\n\n2.\nh(x)=(√(x))/(x-5)\n\nD:x\geq0\ \wedge\ x-5\neq0\to x\geq0\ \wedge\ x\neq5\to x\in\left<0;\ \infty\right)\ \backslash\ \{5\}$

$3.\nf(x)=(√(x))/(x^2-5x)\n\nD:x\geq0\ \wedge\ x^2-5x\neq0\to x\geq0\ \wedge\ x(x-5)\neq0\n\n\to x\geq0\ \wedge\ x\neq0\ \wedge\ x\neq5\to x\in\mathbb{R^+}\ \backslash\ \{5\}\n\n4.\ng(x)=(√(x)+5)/(x^2-x-20)\n\nD:x\geq0\ \wedge\ x^2-x-20\neq0\to x\geq0\ \wedge\ (x+4)(x-5)\neq0\n\n\to x\geq0\ \wedge\ x\neq-4\ \wedge\ x\neq5\to x\in\left<0;\ \infty\right)\ \backslash\ \{-4;\ 5\}$

$5.\nh(x)=(3)/(x^2+1)\n\nD:x^2+1\neq0\to x^2\neq-1\to x\in\mathbb{R}\n\n6.\nf(x)=(√(x-2))/(x+1)\n\nD:x-2\geq0\ \wedge\ x+1\neq0\to x\geq2\ \wedge\ x\neq-1\to x\in\left<2;\ \infty\right)$

$7.\ng(x)=(x^2)/(3x^2-x-2)\n\nD:3x^2-x-2\neq0\to (3x+2)(x-1)\neq0\to x\neq-(2)/(3)\ \wedge\ x\neq1\n\n\to x\in\mathbb{R}\ \backslash\ \{-(2)/(3);\ 1\}\n\n8.\nh(x)=3(x-4)^2-7\n\nD:x\in\mathbb{R}$

How many sides does a regular polygon have that has an angle of 20