Gas burning in an engine is an example of a chemical change
phase change
physical change
nuclear change
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Chemists have identified 118 elements. These elements have been organized by their size and property into a chart called the periodic table. All matter is created from these elements which include solid, liquid, and gas. Some elements naturally combine into compounds.
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V and n
T and V
P and V
P and n
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PV = nRT
Therefore, the following are classified as:
P and T = directly proportional
V and n = directly proportional
T and V = directly proportional
P and V = inversely proportional
P and n = directly proportional
The following pairs of properties as
- directly proportional :
P and T
V and n
T and V
P and n
- inversely proportional :
P and V
Further explanation
Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated), among others
- Boyle's law at constant T, P = 1 / V
- Charles's law, at constant P, V = T
- Avogadro's law, at constant P and T, V = n
So that the three laws can be combined into a single gas equation, the ideal gas equation
In general, the gas equation can be written
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.082 l.atm / mol K
T = temperature, Kelvin
Proportional Comparisons / Directly proportional are comparisons of two or more numbers where one number increases, the other numbers also increase at the same rate
Can be formulated
Inversely proportional is the comparison of two or more numbers where one number increases, the other number decreases in value
Can be formulated
The following pairs of properties as directly or inversely proportional.(from ideal gas equation)
P and T : directly proportional
PV=nRT
V and n : directly proportional
PV=nRT
T and V : directly proportional
PV=nRT
P and V : inversely proportional
P and n : directly proportional
PV=nRT
Learn more
Which equation agrees with the ideal gas law
Which law relates to the ideal gas law
Keywords : ideal gas law, directly proportional, inversely proportional.
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Answer:
The correct answer is because they work at different pH levels.
Explanation:
The pH varies because the different enzymes secreted in the stomach work at different pH levels. Gastric secretion is the most important stage of digestion since when the food comes into contact with a low pH and the enzymes present, they dissociate it and denature the proteins present.
Have a nice day!
Answers
For 2*32=64 grams of oxygen, you can burn 2*16=32 grams of methane (that is, half).
So, our answer is .5g.
Other intermediate calculations are mollecular masses:
Answer:
0.28 g of
Explanation:
You need a balanced equation first. ⇒
You need to find the number of moles of oxygen, which is mass divided by the Mr: 1 ÷ 32 = 1/32
Then you find the moles of methane using the mole ration oxygen to methane 2:1. 1/32 ÷ 2 = 1/64
Then you find the mass by multiplying the Mr with the number of moles:
1/64 × 18 = 0.28125 g = 0.28 g
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Answer:
The Carnot engine operates based on the principles of the Carnot cycle, which is a theoretical idealized thermodynamic cycle. To calculate the work done by the engine, we need to use the formula for the efficiency of the Carnot cycle.
The efficiency of a Carnot engine is given by the equation:
Efficiency = 1 - (T2 / T1),
where T2 is the exhaust temperature in Kelvin and T1 is the burn temperature in Kelvin.
First, we need to convert the temperatures from Celsius to Kelvin.
The burn temperature is 1957 ˚C, so we add 273 to convert it to Kelvin:
T1 = 1957 + 273 = 2230 K.
The exhaust temperature is 500 ˚C, so we add 273 to convert it to Kelvin:
T2 = 500 + 273 = 773 K.
Now we can calculate the efficiency:
Efficiency = 1 - (T2 / T1) = 1 - (773 / 2230).
Next, we need to calculate the heat input, which is the energy released by burning 1 kg of methane.
The energy released by burning methane can be calculated using the heat of combustion of methane, which is -891 kJ/mol.
To convert this to joules per kilogram, we need to know the molar mass of methane, which is 16 g/mol.
1 kg of methane is equal to 1000 g, so the number of moles of methane in 1 kg is:
1000 g / 16 g/mol = 62.5 mol.
The heat released by burning 1 kg of methane is:
-891 kJ/mol * 62.5 mol = -55,687.5 kJ.
To convert this to joules, we multiply by 1000:
-55,687.5 kJ * 1000 = -55,687,500 J.
Now we can calculate the work done by the engine:
Work = Efficiency * Heat input.
Substituting the values we calculated:
Work = (1 - (773 / 2230)) * (-55,687,500 J).
Finally, we can calculate the work done by the engine in joules.
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