It has been determined that the body can generate 5500 kJ of energy during one hour of strenuous exercise. Perspiration is the body’s mechanism for eliminating this heat. What mass of water would have to be evaporated through perspiration to rid the body of the heat generated during 2 hours of exercise? (The heat of vaporization of water is 40.6 kJ/mol.)
Answers
Answer:
4.88 kg
Explanation:
Amount of energy generated in 1 hour of exercise = 5500 kJ
Thus,
Amount of energy generated in 2 hours of exercise = 5500*2 kJ
So,
Amount of energy generated in 2 hours of exercise = 11000 kJ
Heat of vaporization of water = 40.6 kJ/mol
40.6 kJ of energy is required to vaporize 1 mole of water
Also,
11000 kJ of energy is required to vaporize (1/40.6) * 11000 mole of water
Moles of water = 270.936 moles
Molar mass of water = 18 g/mol
Mass = Moles * Molar mass = 270.936 * 18 g = 4876.8473 g
Also,
1 g = 0.001 kg
So, mass of water = 4.88 kg
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Answers
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Explanation:
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