Water coming out from a fountain is modeled by the function f(x)= -x^2+5x+4 where f(x) represents the height, in feet, of the water from the fountain at different times x, in seconds. What does the average rate of change of f(x) from x=3 to x=5 represent?A. The water falls down with an average speed of 3 ft./s from three seconds to five seconds.
B. The water falls down with an average speed of 5 ft./s from three seconds to five seconds.
C. The water travels an average distance of 3 feet from 3 seconds to 5 seconds.
D. The water travels an average distance of 5 feet from 3 seconds to 5 seconds.

Answers

Answer 1
Answer: Hello,

Answer A
(6 ft in 2s)


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Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1?It has no solution. It has one solution. It has two solutions. It has infinitely many solutions.

Which constants can be multiplied by the equations so one variable will be eliminated when the systems are added together?5x + 13y = 232
12x + 7y = 218
The first equation can be multiplied by –13 and the second equation by 7 to eliminate y.
The first equation can be multiplied by 7 and the second equation by 13 to eliminate y.
The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.
The first equation can be multiplied by 5 and the second equation by 12 to eliminate x.

Answers

The THIRD sentence is correct.
The first equation can be multiplied by -12 and the second equation by 5, to eliminate x.
Let's do this:
(1st equation) 5*x + 13*y = 232 / *(-12)
(2nd equation) 12*x + 7*y = 218 / *(5)
---------------------------------
When multiplied, we get:
(1st equation) -60*x - 156*y = -2784
(2nd equation) 60*x + 35*y = 1090
---------------------------------
Further, first equation now will be obtained when ADDING 1st and 2nd equation together:
(1st equation) -60x+60x-156y+35y=-2784+1090
2nd equation we get from just writing any equation from the beginning, for example, the second one:
(2nd equation) 12*x + 7*y = 218
-----------------------------------------
(1st equation) 0*x - 121*y = -1694
(2nd equation) 12*x + 7*y = 218
------------------------------------------
(1st equation) -121*y = -1694 [x variable is in this step eliminated]
(2nd equation) 12*x + 7*y = 218
----------------------------------------------
(1st equation) y = 1694/121
(2nd equation) 12*x + 7*y = 218
----------------------------------------------
(1st equation) y = 14
(2nd equation) 12*x + 7*14 = 218
----------------------------------------------
(1st equation) y = 14
(2nd equation) 12*x + 98 = 218
----------------------------------------------
(1st equation) y = 14
(2nd equation) 12*x = 218 - 98
----------------------------------------------
(1st equation) y = 14
(2nd equation) 12*x = 120
----------------------------------------------
(1st equation) y = 14
(2nd equation) x = 120/12
----------------------------------------------
(1st equation) y = 14
(2nd equation) x = 10
----------------------------------------------
So, solution of the system of this two equations is obtained, and it is:
(x,y)=(10,14)

Answer:

The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.

Debra and Ian shared in $1,000,000 estate. If Ian received $125,000 and debra the rest, what fraction of the estate did Debra receive?

Answers

Answer: Fraction of the estate Debra will received is (7)/(8)

Step-by-step explanation:

Since we have given that

Amount shared by Debra and Lan = $1000,000

Amount received by Lan = $125,000

According to question, Debra received the rest.

So, Amount received by Debra is given by

\$1000000-\$125000\n\n=\$875000

Fraction of the estate Debra will receive is given by

(875000)/(1000000)\n\n=(875)/(1000)\n\n=(35)/(40)\n\n=(7)/(8)

Hence, Fraction of the estate Debra will received is (7)/(8)

Debra received 7/8
if you divide 1,000,000 by 125,000 you get 8. which means Ian got 1/8 of the money. leaving 7/8 for Debra

What is the value of y in the equation 2(3y-4)=10

Answers

2(3y-4)=10\ \ \ |divide\ both\ sides\ by\ 2\n\n(2(3y-4))/(2)=(10)/(2)\n\n3y-4=5\ \ \ \ \ |add\ 4\ to\ both\ sides\n\n3y=9\ \ \ \ \ |divide\ both\ sides\ by\ 3\n\n\boxed{y=3}
If you distribute the 2 on the left you end up with

6y-8=10

then add 8 to both sides

6y=18

then divide by 6 on both sides

y=3

and if you plug it back in it should equal 10

2((3)(3)-4)=10

10=10

What is the simplified form of the equation fraction 4 over 5 n minus fraction 3 over 5 equals fraction 1 over 5 n?n = 1
n = −3
n = fraction 3 over 4
n = fraction 1 over 4

Answers

If you would like to know the simplified form of the equation, you can calculate this using the following steps:

4/5n - 3/5 = 1/5n     /*5n
4 - 3/5 * 5n = 1
4 - 3n = 1
4 - 1 = 3n
3 = 3n
n = 1

The correct result would be n = 1.

Answer:

n=1

Step-by-step explanation:

What is the algebraic expression for the following word phrase the quotient of 3 and z

Answers

Answer:

(3)/(z).

Step-by-step explanation:

Given : phrase the quotient of 3 and z.

To find :what is the algebraic expression for the following word phrase .

Solution : We have given

Phrase the quotient of 3 and z.

We get the quotient when we divide the two terms.

So , We need to divide 3 and z to get the quotient.

Quotient = (3)/(z).

Therefore,  (3)/(z).

The algebraicexpression for the word phrase "the quotient of 3 and z" is 3/z or 3 ÷ z.

We have,

The word "quotient" indicates division, so we know that we need to perform a division operation.

In this case, we are dividing the number 3 by the variable z.

In algebraic notation, the division is typically represented using the forward-slash (/) or the division symbol (÷).

Therefore, we can write "the quotient of 3 and z" as 3/z or 3 ÷ z.

Both expressions convey the idea that we are dividing 3 by the value of z.

Thus,

The algebraicexpression for the word phrase "the quotient of 3 and z" is 3/z or 3 ÷ z.

Learn more about expressions here:

brainly.com/question/3118662

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27 is the relationship linear, exponential, or neither? Options: a. Linear b. Exponential c. Neither

Answers

Answer: Here's my answer

Step-by-step explanation:

The relationship given, 27, is neither linear nor exponential.

In a linear relationship, the dependent variable (y) changes at a constant rate for every unit increase in the independent variable (x). This results in a straight line when plotted on a graph. However, the given value, 27, does not provide any information about how the variable changes in relation to another variable. Without this information, we cannot determine if the relationship is linear.

In an exponential relationship, the dependent variable (y) changes at an increasing or decreasing rate based on a constant ratio for every unit increase in the independent variable (x). This results in a curved line when plotted on a graph. Since the given value, 27, does not provide any information about the rate of change or the constant ratio, we cannot determine if the relationship is exponential.

Therefore, based on the given information, the relationship 27 is neither linear nor exponential.