If a neutral atom has a mass of 12 amu and an atomic number of 5, determine the number of protons, neutrons, and electrons in the atom.
Answers
Answer:
Number of neutrons = 7
The number of protons = The number of electrons = 5
Explanation:
Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.
However, when we talk about the atomic number of the ion, it is not equal to the number of electrons as electron can be gained or loosed.
This is why, more appropriately, the number of the protons which are present in the nucleus of the atom is called the atomic number.
Thus, atomic number = 5
Since, it is a neutral atom, The number of protons = The number of electrons = 5
Mass number is the number of the entities present in the nucleus which is the equal to the sum of the number of protons and electrons.
Mass number = Number of protons + Number of neutrons
12 = 5 + Number of neutrons
Number of neutrons = 7
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Hi there, thanks for asking a question here on Brainly!
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Answer: Letter C ✅
Hope that helps! ★
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Answers
12.40 + pOH = 14
pOH = 14 - 12.40
pOH = 1.6
[OH⁻] =
[OH⁻] =
[OH⁻] = 2.5x10⁻² M
hope this helps!
Answers
Molarity NaOH = 0.1 M
Number of moles NaOH :
n = M * v
n = 0.1 * 0.054
n = 0.0054 moles of NaOH
Finally we calculate the number of moles of HCl in the solution from the stoichiometry of the reaction :
HCl + NaOH = NaCl + H₂O
1 mole HCl -------- 1 mole NaOH
? moles HCl ------- 0.0054 moles NaOH
moles HCl = 0.0054 * 1 /1
= 0.0054 moles of HCl
Volume of HCl = 125 mL / 1000 = 0.125 L
M ( HCl ) = n / V
M = 0.0054 / 0.125
= 0.0432 M
hope this helps!
N2(g) + 3H2(g)2NH3(g)
What is the percentage yield when 60 kg of ammonia is produced from 60 kg of hydrogen?
A
5.9%
B
17.6%
с
35.3%
D
50.0%
Answers
Answer:
B
17.6%
Explanation:
1. Percentage yield = (Actual yield/theoretical yield) x 100
2. You know actual yield of ammonia (60kg) so you need to work out theoretical yield.
3. mols of hydrogen = m/mr = 60,000/2 = 30,000 mols.
4. 3:2 ratio so (30,000/3) x 2 = 20,000 mols of Ammonia.
5. Therefore mass of ammonia = mr x mols = 20,000 x 17 = 340,000 grams
6. So percentage yield is (60,000/340,000) x 100 = 17.6
Answers
The common uses of base if for the formation of salts in a neutralisation reaction.
What is neutralisation reaction?
Neutralisation reaction is a type of chemical reaction whereby salt and water is formed from the reaction of an acid and a base.
For example the reaction between NaOH and HCl leads to the formation of a salt called NaCl.
Therefore, the common uses of base if for the formation of salts in a neutralisation reaction.
Learn more about neutralisation reaction here:
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