A 4.0 kg bucket of water is raised from a wellby a rope.
The acceleration of gravity is 9.81 m/s?.
If the upward acceleration of the bucket is
2.8 m/s², find the force exerted by the rope
on the bucket of water.
1. 69.658
2. 52.84
3. 85.318
4. 70.86
5. 84.429
Answers
Explanation:
Draw a free body diagram of the bucket. There are two forces:
Tension force T pulling up.
Weight force mg pulling down.
Sum of forces in the y direction:
∑F = ma
T − mg = ma
T = mg + ma
T = m (g + a)
Given m = 4.0 kg, g = 9.81 m/s², and a = 2.8 m/s²:
T = (4.0 kg) (9.81 m/s² + 2.8 m/s²)
T = 50.44 N
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