A cab charges $1.75 for the flat fee and $0.25 for each mile. Write and solve an inequality to determine how many miles Eddie can travel if he has $15 to spend.a. $1.75 + $0.25x ≤ $15; x ≤ 53 miles
b. $1.75 + $0.25x ≥ $15; x ≥ 53 miles
c. $0.25 + $1.75x ≤ $15; x ≤ 8 miles
d. $0.25 + $1.75x ≥ $15; x ≥ 8 miles

Answers

Answer 1
Answer:

The inequality for the given situation is $1.75 + $0.25x ≤ $15; x ≤ 53 miles. Therefore, option A is the correct answer.

Given that, a cab charges $1.75 for the flat fee and $0.25 for each mile.

We need to write and solve an inequality to determine how many miles Eddie can travel if he has $15 to spend.

What is inequality?

Inequalities are mathematical expressions in which both sides are notequal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

Now, number of miles = (15-1.75)/0.25

=53 miles

According to the given question, the inequality is 1.75 + 0.25x ≤ 15 and x ≤ 53.

The inequality for the given situation is $1.75 + $0.25x ≤ $15; x ≤ 53 miles. Therefore, option A is the correct answer.

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Answer 2
Answer: $1.75 + $0.25x ≤ $15; x < 53

So the first one. Because you must pay the flat fee, and then for x miles you must pay $0.25. When you do (15-1.75) / 0.25 the answer is 53.

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An education budget went from $800,000 to $900,000. What is the approximate percent increase?

Answers

Answer:

A

Step-by-step explanation:

The increase would be possibly about by 100,000 dollars, but if you were to take it as a decimal as a millionth, it would go up by 10 percent.

For the function y = 4x – 11, what is the output when the input is 10?

Answers

= 4x - 11

x is the input, y is the output.

So if you want to know what input is needed to get an output of 10, set y to 10 and solve for x:

10 = 4x - 11

21 = 4x

x = 21/4

If f(x) = x3 – 2x2, which expression is equivalent to f(i)? A) –2 + i
b) –2 – i
c) 2 + i
d) 2 – i

Answers

Answer

d) 2 – i


Explanation

f(x) = x³ – 2x²

When x = i, we proceed as follows.

Note: i =

          i² =(√-1)(√-1) =  -1

          i³ = (√-1)(√-1)(√-1) = -1(√-1) = -1i = -i

f(x) = x³ – 2x²

f(i) = i³ – 2i²

     = -i – 2(-1)

     = -i + 2

      = 2 – i


Answer:

f(i)=2-i

d is the correct option.

Step-by-step explanation:

The given function is f(x)=x^3-2x^2

Substitute x = i, to find f(i)

f(i)=i^3-2(i)^2

We can rewrite this as

f(i)=i^2\cdot i-2(i)^2

Now, we know thati^2=-1. Thus, we have

f(i)=(-1)\cdot i-2(-1)

On simplifying, we get

f(i)=-i+2\n\nf(i)=2-i

d is the correct option.

A box of uncooked spaghetti cost $0.1369 per ounce. how much is this cost to the nearest cent?

Answers

The cost to the nearest sent is 0.14

This is because you can round the .136 up to the nearest hundredths place.

Factorise fully 6a+10ab

Answers

Answer:

Taking 2a common from the two terms of the equation

6a + 10ab \n  = 2a(3 + 5b)

2a(3+5b) is the right answer.

Final answer:

To factorize 6a + 10ab fully, we can factor out 2a from both terms, resulting in 2a(3 + 5b).

Explanation:

To fully factorize the expression 6a + 10ab, we can start by finding the greatest common factor (GCF) of the two terms. The GCF here is 2a, so we can factor out 2a from both terms:



6a + 10ab = 2a(3 + 5b)



Therefore, the fully factored form of 6a + 10ab is 2a(3 + 5b).

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A runner has a track lap of one minute while at a run, five minutes while at a jog, 7 minutes while at a walk. If 2/5 of the lap is paced at a run, 1/2 at a jog and 1/10 at a walk what is the total track lap time of the runner. Write the solution as a mixed number or a fraction in lowest terms

Answers

24 seconds running
2 minutes 30 seconds jogging
42 seconds walking
3 minutes 36 seconds in that lap

Final answer:

The total track lap time of the runner is 2 2/5 minutes or 2.4 minutes.

Explanation:

The total track lap time of the runner can be calculated by summing up the individual time spent at each pace (run, jog, walk). Each pace's time is first multiplied by the fraction of the lap completed at that pace.

For the run, the calculation is 2/5 of 1 minute which is 2/5 minute.

For the jog, the calculation is 1/2 of 5 minutes which is 5/2 = 2 1/2 minutes or 2.5 minutes in decimal form.

For the walk, the calculation is 1/10 of 7 minutes which is 7/10 = 0.7 minutes.

Adding these times together gives a total of (2/5) + (5/2) + (7/10) = 12/5 = 2 2/5 minutes or 2.4 minutes in decimal form.

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