Help how would you find out the answer to the following question- Janice has three coins in her pocket and they are all different from each other. Jeremy has three coins in his pocket and they are all the same as each other. Jeremy has twice as much money as janice. What are the coins they each have?

Answers

Answer 1

Answer: Rebecca has a 50 pence coin, a 20 pence coin, and a 5 pence coin.
Jeremy has three 50 pence coins.

Answer 2

Answer:

Final answer:

To answer the problem, the coins of Janice must be a penny, dime, and a nickel which total up to $0.16, while Jeremy's coins are three dimes and two pennies totaling $0.32

Explanation:

The problem can be approached by considering the different coins you have available and their values. In the U.S, these are penny ($0.01), nickel ($0.05), dime ($0.10), quarter ($0.25), half dollar ($0.50), and dollar ($1.00). Because Jeremy's coins are all the same and twice Jane's total, this limits us to lower value coins.

Let's start with Jane. She can't have a quarter because Jeremy doesn’t have $0.50 coins. If she had a dime, Jeremy would need two dimes but we know all his coins are the same so this isn't possible. This means Jane must have a penny ($0.01), a nickel ($0.05) and a dime ($0.10) for a total of $0.16. Therefore, Jeremy, whose total is twice Jane's, must have $0.32 which can be achieved by having three dimes ($0.10 x 3 = $0.30) and two pennies ($0.01 x 2 = $0.02).

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