Where does oxidation occur in an electrochemical cell?(1) at the cathode in both an electrolytic cell and a voltaic cell
(2) at the cathode in an electrolytic cell and at the anode in a voltaic cell
(3) at the anode in both an electrolytic cell and a voltaic cell
(4) at the anode in an electrolytic cell and at the cathode in a voltaic cell

Answers

Answer 1

Answer: Option No. 1 at the cathode in both an electrolytic cell and a voltaic cell

Negative ion arrives at the anode, attracted by electrostatic forces, where they lose electrons. Loss of electrons is defined as oxidation.

The reverse process occur at the negative electrode, where positive ions pick up electrons. They are reduced.

Answer 2

Answer:

Answer : The correct option is, (3) at the anode in both an electrolytic cell and a voltaic cell.

Explanation :

As we know that there are two types of cell which are, electrolytic cell and electrochemical cell or galvanic cell.

Electrolytic cell : It is defined as the cell in which the chemical reaction occurs by passing of the current from external source.

In this electrolytic cell, the oxidation occurs at anode which is a positive electrode and reduction occurs at cathode which is a negative electrode.

Electrochemical cell : It is defined as the cell in which the chemical reaction occurs with the production of electric potential difference between the two electrodes. It is also known as voltaic cell.

In this cell, the oxidation occurs at anode which is a negative electrode and reduction occurs at cathode which is a positive electrode.

From this we conclude that, the oxidation occurs at the anode in both an electrolytic cell and a voltaic cell.

Hence, the correct option is, (3) at the anode in both an electrolytic cell and a voltaic cell.

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What is the pressure in atm exerted by 2.48 moles of a gas in a 250.0 ml container at 58c?

Answers

Explanation:

The given data is as follows.

V = 250.0 ml, T = 58^{o}C = 58 + 273 = 331 K

n = 2.48 moles, P = ? , R = 0.082 atm L /K mol

Therefore, calculate the pressure using ideal gas equation as follows.

PV = nRT

P = $(nRT)/(V)$

= $(2.48 mol * 0.082 atm L/K mol * 331 K)/(250.0 ml)$

= 0.269 atm

Thus, we can conclude that pressure of the given gas is 0.269 atm.

T = 58 + 273.15 = 331.15

R = 0.082 atm

V = 250.0 mL / 1000 = 0.25 L

P = n x R x T / V

P = 2.48 x 0.082 x 331.15 / 0.25

P = 67.342 / 0.25

P = 269.368 atm

hope this helps!

Which radioisotope emits alpha particles?
(1) Fe-53 (3) Au-198
(2) Sr-90 (4) Pu-239

Answers

Answer : Option 4) Pu-239

Explanation : Plutonium-239 is a radioisotope of the element plutonium which emits alpha particles. The decaying process of Pu-239 emits alpha particles. It is widely used as a nuclear reactor fuel. Pu-239 is also used as a primary fissile isotope for the production of nuclear weapons.

The answer is (4) Pu-239. The decay mode of Pu-239 is α decay which means it will emit alpha particles. The other three have the decay mode of β decay.

Unknown element X combines with oxygen to form the compound XO2. If 44.0 grams of element X combines with 8.00 grams of oxygen, what is the atomic mass of element X?A. 16 amu
B. 44 amu
C. 88 amu
D. 176 amu
E. 352 amu

Answers

Oxygen has a Mr of 16 and half of 16 is 8 which is how many grams used. If 44 grams of X is used it must have an amu of 88. (Times 2)

Which of the following metal atoms would have the highest conductivity?A.the atom with the smallest radius and the fewest valence electrons
B.the atom with the smallest radius and the most valence electrons
C.the atom with the largest radius and the fewest valence electrons
D.the atom with the largest radius and the most valence electrons

Answers

Answer: Option (d) is the correct answer.

Explanation:

A metal which has the largest size and the most valence electrons would have the highest conductivity because the larger is the size of a metal the more freely electrons can move in it. Hence, the metal can conduct electricity.

If the atom is smaller in size then the electrons will be tightly held around the nucleus and hence they won't be able to move freely. Therefore, they will not conduct electricity.

Thus, we can conclude that the atom with the largest radius and the most valence electrons would have the highest conductivity.

Answer:

D. the atom with the largest radius and the most valence electrons

Explanation:

Phosphoric acid is a triprotic acid with Ka1 = 6.9 x 10-3, Ka2 = 6.2 x 10-8, and Ka3 = 4.8 x 10-13. Calculate the pH of a solution created by dissolving 23.4 g of KH2PO4(s) and 38.4 g of Na2HPO4(s) in 2 L of water.