During a laboratory experiment, a student findsthat at 20° Celsius, a 6.0-meter length of copper
wire has a resistance of 1.3 ohms. The crosssectional
area of this wire is
(1) 7.9 × 10^−8 m2 (3) 4.6 × 10^0 m2
(2) 1.1 × 10^−7 m2 (4) 1.3 × 10^7 m2

Answers

Answer 1

Answer:

The cross-sectional area of the copper wire is which has 1.3 ohm at 20 degree Celsius during laboratory experiment by student is 7.9×10⁻⁸ ohm.

What is the resistance?

Resistance is obstacle for the current flow in the circuit. It is the measure of reverse act to current flow in through a material. It can be given as,

$R=\rho(L)/(A)$

Here, (ρ) is the specific resistance (l) is the length of the wire and (A) is the cross-sectional area of the wire.

During a laboratory experiment, the student finds that at 20° Celsius, a 6.0-meter length of copper wire has a resistance of 1.3 ohms.

The value of resistivity of copper wire is 1.72×10⁻⁸ ohm-m. Put these values in the above formula as,

$R=\rho(L)/(A)\n1.3=1.72*10^(-8)*(6)/(A)\nA=7.9*10^(-8)\rm \; m^2$

Thus, the cross-sectional area of the copper wire is which has 1.3 ohm at 20 degree Celsius during laboratory experiment by student is 7.9×10⁻⁸ ohm.

Learn more about the resistance here;

brainly.com/question/17563681

Answer 2

Answer:

ρ = resistivity of copper at 20 °C = 1.72 x 10⁻⁸ ohm-m

R = resistance of the copper wire = 1.3 ohm

L = length of the copper wire = 6 meter

A = area of cross-section of the copper wire = ?

Resistivity of copper wire is given as

R = ρL/A

inserting the values in the above equation

1.3 = (1.72 x 10⁻⁸) (6)/A

A = 7.9 x 10⁻⁸ m²

Hence the correct choice is

(1) 7.9 x 10⁻⁸ m²

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As a 2-kg ball rolls down a ramp, the net force on it is 10 N. What is the acceleration?

Answers

That all depends on the direction of the force. If the force is parallel to the ramp, then the acceleration of the ball is 5 m/s^2. If the force isn't parallel to the ramp, then the acceleration is less.

On the Celsius scale, one degree indicates the same temperature change as A. one degree Fahrenheit.
B. 5/9 degree Fahrenheit.
C. one kelvin.
D. 9/5 kelvin.

Answers

Choice ' C ' is the only correct one.

The Celsius degree and the Kelvin are also the
same size as 9/5 (1.8) Fahrenheit degrees.

D) 9/5 kelvin is WRONG

When Tito lifts the heaviest object he can, he is testing his _____.

Answers

When Tito lifts the heaviest object he can, he is probably testing his ability to lift weight. In other words, he could also be testing his upper body muscle strength. The process is called weight-lifting and it is designed to test the muscle strength of your upper body.

Explanation : When Tito lifts the heaviest object, he is testing his strength.

We know, strength is the quality of the physical energy and potential of the person. The strength of the person is power and his capacity.

So, we can say that When Tito lifts the heaviest objects then he is testing his strength, potential, and power.

John’s mass is 95.6 kg, and Barbara’s is 55.3 kg. He is standing on the x axis at xJ = +10.9 m, while she is standing on the x axis at xB = +2.50 m. They switch positions. How far and in which direction does their center of mass move as a result of the switch? Distance moved by center of mass =

Answers

Answer:Shifted towards Left by distance of 2.243 m

Explanation:

Given

Mass of john $m_1=95.6 kg$

Mass of barbara $m_2=55.3 kg$

John is standing at $x=10.9 m$

Barbara is standing at $x=2.50 m$

$x_(com)=(m_1x_1+m_2x_2)/(m_1+m_2)$

$x_(com)=(95.6* 10.9+55.3* 2.5)/(95.6+55.3)$

$x_(com)=(1180.29)/(150.9)$

$x_(com)=7.821 m$

Now if they change their Position then

$x'_(com)=(95.6* 2.5+55.3* 10.9)/(95.6+55.3)$

$x'_(com)=(841.77)/(150.9)$

$x'_(com)=5.578$

Thus we can see that center of mass shifted towards left by a distance of $2.243 m$ because heavier is shifted towards left

a block of mass 5kg slides down an inclined plane that has an angle of 10 degrees if the inclined plane has no friction and the block starts at a height of 0.8m how much kinetic energy does the block have when it reaches the bottom? acceleration due to gravity is 9.8m/s2. someone help me how to solve this, physics conservation of energy

Answers

The physics conservation of energy E = 39.2 joules.

To calculate the Physics conservation of energy.

Mass of the block, m = 5 kg

At the top, the block will have only potential energy which is given by :

P=mgh

At the bottom of the inclined plane, it will have only kinetic energy which is given by :

E=(1/2)mv2

Applying the conservation of energy as :

E=(1/2)mv2=mgh

E=5*9.8*0.8

E = 39.2 joules.

The physics conservation of energy E = 39.2 joules.

To learn more about The physics conservation of energy refer:brainly.com/question/4301920

#SPJ2

In this case, the inclined plane is frictionless and therefore energy is perfectly conserved with no losses. The block originally starts off with some gravitational potential energy, which is then completely converted into kinetic energy. So the initial gravitational potential energy is equal to the final kinetic energy.

$PE_(initial) = KE_(final)$
$PE_(initial) =mgh=(5kg)(9.8m/ s^(2) )(0.8m)=39.2 joules$
$KE_(final)=39.2joules$

Humans can perceive infrared light with their eyes. True or false