A car enters a tunnel at 24 m/s and accelerates steadily at 2.0 m/s2. At what speed does it leave the tunnel, 8.0 seconds later?

Answers

Answer 1

Answer: Given:

V1 = initial velocity = 24 m/s
a = acceleration = 2.0 m/s^2
s = time = 8 s
V2 = final velocity = ?

For linear-motion problems with those given terms, the following formula is used:

V2 = V1 + as

Substituting the given values:

V2 = 24 + 2(8)
V2 = 24 + 16
V2 = 40 m/s

Therefore the car will have a speed of 40 m/s as it leaves the tunnel.

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Answers

Answer:

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Explanation:

Stress, $\sigma=\frac {F}{A}$

Where F is force and A is area. Also, F=mg where m is mass and g is acceleration due to gravity

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$Strain=\frac {\triangle l}{l}$ where $\triangle l$ is the elongation and l is the original length

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Answers

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