CHEMISTRY HIGH SCHOOL

Which process occurs at the anode in an electrochemical cell?(1) the loss of protons
(2) the loss of electrons
(3) the gain of protons
(4) the gain of electrons

Answers

Answer 1
Answer:

The process that occurs here in the anode of an electrochemical cell is the loss of electrons (Option 2).

What is an anode?

An anode is a negative pole that is known to be polarized in the electrochemical device of a given outside circuit.

  • Conversely, the cathode is the positive pole where electrons flow in a given current.

In conclusion, the process that occurs here in the anode of an electrochemical cell is the loss of electrons (Option 2).

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Answer 2
Answer:

The process that occurs at the anode in an electrochemical cell is the loss of electrons. The answer is number 2. Oxidation occurs as electrons are lost at the anode at one of the electrodes in both an electrolytic cell and a voltaic cell.

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505 Kl expressed in liters

Answers

505000.0 L answer...

What is the molar mass of a substance

Answers

Molar mass of a molecule is the sum of the atomic mass of the individual elements in the molecule.  

Atomic mass of Pb = 207  amu

Atomic mass of N = 14  amu

Atomic mass of O = 16  amu

Here amu stands for atomic mass unit

Molar mass of Pb(NO₃)₂ = 207 + [14 + (16 x 3)] x 2  

                                         = 207 + 28 + (48) x 2 = 331 g/mol  
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What are cumulative pollutant examples?

Answers

a very fatal disese that causes you to poop blood 

How many grams of CuSO4 are there in 100.0 g of hydrate? How many moles?

Answers

the hydrate form of CuSO4 has 5 water molecules (CuSO4-5H20) copper (II) Sulfate pentahydrate or commonly known as blue vitriol. 

To solve, the following molar masses are to be known. 
CuSO4.5H2O (hydrate)  - 249.7g/mole
CuSO4 (anhydrous) -159.6g/mole
Also there molar ratio of the hydrate and CuSO4 is 1. 

the mass of the hydrate is to be divided by the molar mass of the hydrate then multiplied by the ratio (1) to get the moles of hydrate and multiplied by the molar mass of the anhydrous to get the mass in grams. 

moles = (100g/249.7)*1 =  0.4 moles hydrate
grams = 0.4*159.6 =  64.9 grames hydrate

Is combustion an example of the law of conservation of matter and why?

Answers

Answer:

Explanation:

The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. For example, when wood burns, the mass of the soot, ashes, and gases, equals the original mass of the charcoal and the oxygen when it first reacted.

How much energy (in Joules) would it take to warm 3.11 grams of gold by 7.7 oC(specific heat capacity of gold = 0.130 J/g °C)

Answers

Answer:

It would take 3.11 J to warm 3.11 grams of gold

Explanation:

Step 1: Data given

Mass of gold = 3.11 grams

Temperature rise = 7.7 °C

Specific heat capacity of gold = 0.130 J/g°C

Step 2: Calculate the amount of energy

Q = m*c*ΔT

⇒ Q = the energy required (in Joules) = TO BE DETERMINED

⇒ m = the mass of gold = 3.11 grams

⇒ c = the specific heat of gold = 0.130 J/g°C

⇒ ΔT = The temperature rise = 7.7 °C

Q = 3.11 g * 0.130 J/g°C * 7.7 °C

Q = 3.11 J

It would take 3.11 J to warm 3.11 grams of gold
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