CHEMISTRY HIGH SCHOOL

At 225.0 °C a gas has a volume of 400.0 mL. What is the volume of this gas at 127.0 °C?

Answers

Answer 1

Answer:

The volume of the gas at 127.0 °C is 321.28 ml.

What is volume?

The volume of any substance is the total space it occupies.

Given data is

V₁ is 400.0 mL

T₁ is 225.0ºC + 273 = 498 K

T₂ = 127.0ºC + 273 = 400 K

To find V₂

By Ideal gas law

$\rm (V_1)/(T_1 ) =(V_2)/(T_2)$

$\rm (400.0)/(498 ) =(V_2)/(400)\n\n\n (160000)/(498)= 321.28 ml$

Thus, the volume of the gas at 127.0 °C is 321.28 ml.

Learn more about volume, here:

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Answer 2

Answer: V₁ = 400.0 mL

T₁ = 225.0ºC + 273 = 498 K

V₂ = ?

T₂ = 127.0ºC + 273 = 400 K

V₁ / T₁ = V₂ / T₂

400.0 / 498 = V₂ / 400

498 x V₂ = 400 x 400

498 x V₂ = 160000

V₂ = 160000 / 498

V₂ = 321.28 mL

hope this helps!

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Answers

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hope this helps!

what is the volume of a gas at 2.00 atm and 200.0 K if its original volume was 300.0 L at 0.250 atm and 400.0 K

Answers

Given:
P1 = 2.00 atm
T1 = 200.0 K
V2 = 300.0 L
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Required:
V1

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Answers

Number of moles:

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hope this helps!

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Answers

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Answers

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Answers

Answer:

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Explanation:

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