A 50.0-gram block of copper at 10.0°C is carefully lowered into 100.0 grams of water at 90.0°C in an insulated container. Which statement describes the transfer of heat in this system?(1) The water loses heat to the block until both are at 10.0°C.
(2) The block gains heat from the water until both are at 90.0°C.
(3) The water loses heat and the block gains heat until both are at the same temperature that is between 10.0°C and 90.0°C.
(4) The water gains heat and the block loses heat until both are at the same temperature that is between 10.0°C and 90.0°C.
Answers
1. When 2 or more finite amounts of substances are mix together (with different temperature) the final temperature is never equivalent to the initial temperature of any of the substances involved.
2. The substances meet at an equilibrium temperature.
3. Heat transfers from a higher temperature to a lower temperature.
Only choice (3) satisfies the conditions.
Final answer:
Heat transfers from the water to the copper block until both reach an equilibrium temperature.
Explanation:
The transfer of heat in this system can be described by (4) The water gains heat and the block loses heat until both are at the same temperature that is between 10.0°C and 90.0°C.
This is because heat always flows from the object with higher temperature to the object with lower temperature. In this case, the water at 90.0°C has a higher temperature than the copper block at 10.0°C. As a result, heat will transfer from the water to the copper block, causing the water to cool down and the copper block to heat up. Eventually, both objects will reach an equilibrium temperature somewhere between 10.0°C and 90.0°C.
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------------------
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