Write the net ionic equation for the precipitation reaction that occurs when aqueous solutions of potassium sulfide and chromium(II) nitrate are combined. Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed leave it blank. 2Cr^3+ + 3S^2- (aq) + + rightarrow Cr_2S_4 (s) +
Answers
Answer:
S²⁻(aq) + Cr²⁺(aq) ⇄ CrS(s)
Explanation:
The molecular equation includes all the species in the molecular form. Usually, it is useful to write this first to balance the equation. This is a double displacement reaction.
K₂S(aq) + Cr(NO₃)₂(aq) ⇄ 2 KNO₃(aq) + CrS(s)
The full ionic equation includes all ions and the species that no dot dissociate in water.
2 K⁺(aq) + S²⁻(aq) + Cr²⁺(aq) + 2 NO₃⁻(aq) ⇄ 2 K⁺(aq) + 2 NO₃⁻(aq) + CrS(s)
The net ionic equation includes only those ions that participate in the reaction and the species that do not dissociate in water.
S²⁻(aq) + Cr²⁺(aq) ⇄ CrS(s)
The net ionic equation for the precipitation reaction is: Cr+ + 3S → CrS(s)
The net ionic equation for the precipitation reaction between potassium sulfide and chromium(II) nitrate can be written as:
Cr + 3S → CrS(s)
In this reaction, the chromium(II) ions (Cr) react with the sulfide ions (S) to form chromium(II) sulfide (CrS) which precipitates as a solid.
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Answers
Answer:
M
Explanation:
Henry's law relational the partial pressure and the concentration of a gas, which is its solubility. So, at the sea level, the total pressure of the air is 1 atm, and the partial pressure of O2 is 0.21 atm. So 21% of the air is O2.
Partial pressure = Henry's constant x molar concentration
0.21 = Hx1.38x
H =
H = 152.17 atm/M
For a pressure of 665 torr, knowing that 1 atm = 760 torr, so 665 tor = 0.875 atm, the ar concentration is the same, so 21% is O2, and the partial pressure of O2 must be:
P = 0.21*0.875 = 0.1837 atm
Then, the molar concentration [O2], will be:
P = Hx[O2]
0.1837 = 152.17x[O2]
[O2] = 0.1837/15.17
[O2] = M
Final answer:
The molar concentration of O2 in the surface water of a mountain lake at 20 °C and an atmospheric pressure of 665 torr is approximately 1.21×10-3 M.
Explanation:
To calculate the molar concentration of O2 in the surface water of a mountain lake using Henry's law, we first need to understand how pressure affects the solubility of gases and vice versa.
As per Henry's law, at a constant temperature, the solubility of a gas in a liquid is directly proportional to the pressure of the gas above the liquid. The partial pressure of O2 in air at sea level is 0.21 atm. This means that when the atmospheric pressure is 1 atm, the molar concentration of O2 is 1.38×10−3 M. At higher altitudes, the atmospheric pressure reduces. The given atmospheric pressure at the mountain lake is 665 torr, which is approximately 0.875 atm.
Using these values in Henry's law, the molar concentration of O2 can be calculated as:
C = P * x
where C is molar concentration, P is atmospheric pressure, and x is given solubility at 1 atm. Substituting the values:
C = (0.875 atm) * (1.38×10−3 M) = 1.21x10-3 M approximately
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Answers
Answer:
Which equation represents the reaction of a weak acid with water? the equation is : HCl + H2O H3O+ + Cl- HCO3– + H2O H2CO3 + OH– H2O H + + OH- HCOOH + H2O H3O+ + HCOO
Explanation:
hope it helps : )
Answer:
Hey mate, here is your answer. Hope it helps you.
HCOOH + H2O ↔ H3O+ + HCOO-
Explanation:-
A strong acid is one which completely dissociates into its corresponding ions in aqueous medium.
In contrast, a weak will only partially dissociate such that there is an equilibrium between the dissociated ions and the undissociated acid.
In the given examples:
HCl, HCO3- and H2CO3 are all strong acids. However, HCOOH i.e. formic acid is a weak acid which dissociates in water to form H3O+ and formate ion, HCOO-
HCOOH + H2O ↔ H3O+ + HCOO-
Answers
Energy = mC(T2-T1)
Energy = 255(4.184)(12.5)
Energy = 13336.5 J
Answer: The amount of energy required to raise the temperature is 13323.75 joules.
Explanation :
The amount of energy required to raise the temperature can be calculated as follows.
where,
q = heat energy
m = mass of water
C = specific heat
T = temperature
Remember that the specific heat of water is .
Therefore, putting the values in the above equation as follows.
= 13323.75 joules
So, the amount of energy required to raise the temperature is 13323.75 joules.
Answers
The charge on the most stable ion of bromine is - 1.
What is an ion?
A charged atom or molecule is known as an ion. It has a charge because the atom or molecule's number of protons and electrons is not equal. Depending on whether an atom has more electrons than protons or fewer electrons than protons, an atom might become positively or negatively charged.
An atom is referred to be an ION when it is drawn to another atom due to an imbalance in its electron and proton numbers. A negative ion, or ANION, is an atom that contains more electrons than protons. A positive ion is one that has more protons than electrons.
Either there are too many or not enough electrons in a charged atom. Atoms in DS1 are heated to extremely high energy and unstable state. Then, a cathoderay in the thruster chamber discharges electrons, which strike the. Some of the electrons in the atoms in the chamber are stripped or knocked away when the electrons strike them. Plasma is created when a mass of charged, overheated atoms with free electrons.
Therefore, the charge on the most stable ion of bromine is - 1
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Br (Bromide)
-1 or Br- hope this helps
Answers
Answer:
400 Joules
Explanation:
From the question,
The total kinetic energy of the water balling when hits the ground is given as
K.E = 1/2mv².................. Equation 1
Where K.E = Kinetic Energy of water ballon, m = mass of water balloon, v = velocity of water ballon
Given: m = 2 kilograms, v = 20 meters/second.
Substitute these values into equation 1
K.E = (2×20²)/2
K.E = 2×400/2
K.E = 400 Joules
Answers
Answer:
0.1066 hours
Explanation:
A common pesticide degrades in a first-order process with a rate constant (k) of 6.5 1/hours. We can calculate its half-life (t1/2), that is, the times that it takes for its concentration to be halved, using the following expression.
t1/2 = ln2/k
t1/2 = ln2/6.5 h⁻¹
t1/2 = 0.1066 h
The half-life of the pesticide is 0.1066 hours.
The half-life of the breakdown reaction is 0.1066 h
The half-life of a substance is simply defined as the time taken for half of the original substance to decay.
The half-life of a first order reaction can be obtained by the following equation:
Where:
is the half-life
K is the decay constant
With the above formula, we can obtain the half-life of the breakdown reaction as follow:
Rate constant (K) = 6.5 h¯¹
Half-life (
) =.?
Therefore, the half-life of the breakdown reaction is 0.1066 h
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