The watering can that Carlos uses in his vegetable garden holds 5 of a certain unit of liquid volume. When full, how much water is in the watering can?

Answers

Answer 1

Answer: the watering can can hold 5 units of liquid volume

Answer 2

Answer: It will hold 5 of the certain units

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Write an ex expression for the product of 11 and w

Answers

Answer:

11w

Step-by-step explanation:

product means multiply

Solve the system of equations below.
(x+y=21
2x = 33+ y

Answers

Answer:

(18, 3 )

Step-by-step explanation:

Given the 2 equations

x + y = 21 → (1)

2x = 33 + y → (2)

Rearrange (2) expressing y in terms of x by subtracting 33 from both sides

y = 2x - 33 → (3)

Substitute y = 2x - 33 into (1)

x + 2x - 33 = 21, that is

3x - 33 = 21 ( add 33 to both sides )

3x = 54 ( divide both sides by 3 )

x = 18

Substitute x = 18 into (3) for corresponding value of y

y = (2 × 18) - 33 = 36 - 33 = 3

Solution is (18, 3 )

Answer:

Step-by-step explanation:

x+y = 21 —> (A)

2x = 33 + y — (B)

Form eq B

2x = 33 + y

Or y = 2x - 33

By putting the value of y in equation A

x + 2x -33 = 21

3x = 21 + 33

3x = 54

x = 54/3

x = 18

Now,

y = 2 (18) -33

= 36 - 33

= 3

Thus, s.s ={( 18,3)}

Peter is trying to buy fencing for the perimeter of his garden. His garden is in the shape of a rectangle with a length of 2(x+6)feet and a width of 3.5x feet. How many feet of fencing will he need to buy? Write and simplify an expression to represent this situation? What properties did you use?

Answers

Given that, the length of the garden is 2(x+6)feet and width is 3.5x feet.

So, length : l = 2(x+6) and width = 3.5x.

To find the fence of the garden we need to find the perimeter of the rectangle.

Formula to find the perimeter is:

p = 2l + 2b

= 2*2(x+6) + 2*3.5x

= 4(x+6) + 7x By multiplication.

= 4x + 24 + 7x By distribution property.

= 11x + 24 Combining the like terms.

So, he need to buy 11x + 24 feet fencing.

Hope this helps you!

Using the given zero, find one other zero of f(x). Explain the process you used to find your solution.2 - 3i is a zero of f(x) = x4 - 4x3 + 14x2 - 4x + 13.
*Can someone show the work I have the answers

Answers

The zeros of a function are the points where the function cross the x-axis.

One other zero of $\mathbf{f(x) = x^4 - 4x^3 + 14x^2 - 4x + 13}$ is 2 + 3i.

The zero of $\mathbf{f(x) = x^4 - 4x^3 + 14x^2 - 4x + 13}$ is given as:

$\mathbf{Zero = 2 - 3i}$

The above number is a complex number.

If a complex number a + bi is the zero of a function f(x), then the conjugate a - bi is also the zero of f(x).

This means that, one other zero of $\mathbf{f(x) = x^4 - 4x^3 + 14x^2 - 4x + 13}$ is 2 + 3i.

Read more about zeros of functions at:

brainly.com/question/22101211

Answer:

One other zero is 2+3i

Step-by-step explanation:

If 2-3i is a zero and all the coefficients of the polynomial function is real, then the conjugate of 2-3i is also a zero.

The conjugate of (a+b) is (a-b).

The conjugate of (a-b) is (a+b).

The conjugate of (2-3i) is (2+3i) so 2+3i is also a zero.

Ok so we have two zeros 2-3i and 2+3i.

This means that (x-(2-3i)) and (x-(2+3i)) are factors of the given polynomial.

I'm going to find the product of these factors (x-(2-3i)) and (x-(2+3i)).

(x-(2-3i))(x-(2+3i))

Foil!

First: x(x)=x^2

Outer: x*-(2+3i)=-x(2+3i)

Inner: -(2-3i)(x)=-x(2-3i)

Last: (2-3i)(2+3i)=4-9i^2 (You can just do first and last when multiplying conjugates)

---------------------------------Add together:

x^2 + -x(2+3i) + -x(2-3i) + (4-9i^2)

Simplifying:

x^2-2x-3ix-2x+3ix+4+9 (since i^2=-1)

x^2-4x+13 (since -3ix+3ix=0)

So x^2-4x+13 is a factor of the given polynomial.

I'm going to do long division to find another factor.

Hopefully we get a remainder of 0 because we are saying it is a factor of the given polynomial.

x^2+1

---------------------------------------

x^2-4x+13| x^4-4x^3+14x^2-4x+13

-( x^4-4x^3+ 13x^2)

------------------------------------------

x^2-4x+13

-(x^2-4x+13)

-----------------

So the other factor is x^2+1.

To find the zeros of x^2+1, you set x^2+1 to 0 and solve for x.

$x^2+1=0$

$x^2=-1$

$x=\pm √(-1)$

$x=\pm i$

So the zeros are i, -i , 2-3i , 2+3i

The Question is in the file below. (Khan Academy)

Answers

that little squaer angle means right angle or 90 degrees

the black line and the red line cross

therefor the oposte angles are eqal measure
7x=90+x
solve
minus x
6x=90
divide 6
x=15

x=15

-3x = 2x + 19 solve