A veterinary office is treating dogs and cats. There are 15 more cats than dogs. Altogether, there are 45 animals.Let c represent the number of cats and d represent the number of dogs. The following system of equations represents the situation:

d+c=45

c=d+15

How many cats and dogs are in the clinic?

ignore last question, it was worded wrong. please help!

Answers

Answer 1
Answer: 30 cats and 15 dogs.
Answer 2
Answer: There's 30 cats and 15 dogs

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A number line represents equivalent fractions and decimals by demonstrating the decimal and fractions likeness in the amount the represent.

GeometryQ.1 Pythagorean Theorem F55
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Hakim is decorating a ballroom ceiling with garland. If the rectangular ceiling is 42 feet by 40
feet, how much garland will Hakim need to reach from one corner of the ceiling to the
opposite corner?
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Answer: 58 feet

Step-by-step explanation:

If you flip three fair coins what is the probability that the two first flips will both be heads, and the third flip will be either heads or tales?

Answers

Answer:

The probability that a coin flip is a head or a tail is 0.5. The probability that a coin flip is either a head or a tail is 1. The probability that a three-coin-flip is two heads and a head or a tail is 0.25.

Step-by-step explanation:

Factorising quadratics

X squared + 5x -6
X squared - 2x15
X squared -7x +12

Answers

Answer:

  • (x -1)(x +6)
  • (x -5)(x +3)
  • (x -4)(x -3)

Step-by-step explanation:

In each case, you're looking for divisors of the constant that have a sum equal to the x-coefficient. Those divisors are the constants in the binomial factors.

1) -6 = -1·6 = -2·3 . . . . . (-1)+(6) = 5, so these are the constants of interest.

  x^2 +5x -6 = (x -1)(x +6)

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2) -15 = -1·15 = -3·5 = -5·3 . . . . . (-5)+(3) = -2, so these are the constants of interest

  x^2 -2x -15 = (x -5)(x +3)

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3) 12 = -1·-12 = -2·-6 = -3·-4 . . . . . (-3) +(-4) = -7, so these are the constants of interest

  x^2 -7x +12 = (x -3)(x -4)

I have 1/2-1/7 and3/5-1/2

Answers

(1)/(2)-(1)/(7)=\ \ \ | make\ common \denominator\n\n(7)/(14)-(2)/(14)=(7-2)/(14)=(5)/(14)\n\n(3)/(5)-(1)/(2)= \ \ \ | make\ common \denominator\n\n (6)/(10)-(5)/(10)=(1)/(10)
1/2 - 1/7 = 7/14 - 2/14 = 5/14
3/5 - 1/2 = 6/10 - 5/10 = 1/10

This is like so hard to me i do not get it at all!

Answers

If u don't get it, go back and do some practice problems they have in the lesson. (I am in K12 too, that's wat I do. Sometimes I even do practice problems in the middle of the test.)