Many bicycles have 26 inch diameter wheels. The low gear attached to your pedals has a radius of 2.2 inches. The low rear gear, driven by the chain attached to the front gear, has a diameter of 3 inches. How far does the bike travel in one rotation of the pedals, i.e. the front gear revolves once.

Answers

Answer 1

Answer: The circumference is 'Pi' times diameter.

So one rotation of the pedals will cause the front chain drive to complete one full turn, so it will move the chain the same distance as it's circumference.

So it will move the chain (2.2 Pi )inches. Then the back drive has a circumference of 3pi inches, but it only turns 2.2pi inches. So it turns 2.2pi/3pi = 11/15 of a full rotation. Since the wheel turns at the same rate as the back chain drive, the wheel will turn 11/15 of a full turn as well.

And since the back wheel is 26 inches in diameter, it's circumference is 26pi inches. If it turned a full rotation, it would go this distance along the ground, but it is only going 11/15 of this distance, so it is going (11/15)x 26pi =(286/15)pi inches. Or approximately 59.8997 inches.

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12.75x+250=18.25x74
can someone help with this?

Answers

Answer:

X = 4402/51 = 86.31

Step-by-step explanation:

Write an equation of the direct variation that includes the point (-10,-17).

Answers

We know that when x= -10, y= -17.

So, if we put those into direct variation "y=kx", we get
-17= k(-10)
k = -17 / -10

Now we put the value of "k" into the formula and we get A (y= 17/10x )

1+5=12 2+10=24 3+15=36 5+25=

Answers

5+25=48 becase you add 12 each time

What kind of transformation is this?

Answers

$\huge\boxed{Hello!:)}$

This transformation is called $\huge\bold{Reflection.}$

Reflection simply means an object has been reflected.

Here, the triangle has been reflected.

$\huge\boxed{Thus, \: the\: answer\: is: \: Reflection.}$

$\huge\mathfrak{Good \:luck!}$

$\boxed{UnknownGirl\: here\: to\:help}$

Answer:

Reflection

Step-by-step explanation:

It is a reflection because it is like they are looking in the mirror.

In triangle ABC, angle A = 74°, a = 126, and b = 84. Find angle B.A. 39.9°
B. 79.4°
C. 80.8°
D. impossible to tell

Answers

Triangle ABC
Angle A = 74°
a = 126
b = 84
Use the sine rule
$(a)/(sin A) = (b)/(sin B)$
Plug in the given
$(126)/(sin(74)) = (84)/(sin(B))$
Cross multiply
126 × sin(B) = 84 × sin(74)
Divide by 126
$(126sin(B))/(126) = (84sin(74))/(126)$
126 and 126 cancels out
sin(B) = $(84sin(74))/(126)$
take sin inverse ( $sin^(-1)$ )
B = $sin^(-1)$ ( $(84sin(74))/(126)$ )
B = 39.85° = 39.9°

Answer:

Currently doing the test and got A. 39.9°.

The full process is explained above. This is a confirmation that the other person is correct.

Factor this radical expression. 50a^2-10ab/20a^3b^3

Answers

remembe
(ax)/(bx)=(a/b)(x/x)=(a/b)1
find ones aka common factors and use distributive

top
50a^2-10ab
common facotrs is 10a
undistribute (ab+ac=a(b+c))
10a(5a-b)

bottom
20a^3b^3
see if 10a is also a common factor and undistribute that to cancel and make ones
10a(2a^2b^2)

now we have
$(10a(5a-b))/(10a(2a^(2)b^(3))$ = $(10a)/(10a)$ $(5a-b)/(2a^(2)b^(3))$

1)split into two fractions
$(50a^(2) )/(20a ^(3) b ^(3) )$ - $(10ab )/(20a ^(3) b ^(3) )$

2) cancel what you can on both sides
$(5)/(2ab ^(3) )$ - $(1)/(2a ^(2)b ^(2) )$

3) Make the denominators the same by cross multiplying and then put together as 1 fraction again
$(5a-b)/(2a ^(2)b ^(2) )$

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