At the end of 2012, global population was about 7.0 billion people. What mass of glucose in kg would be needed to provide 1200 cal/person/day of nourishment to the global population for one year? Assume that glucose is metabolized entirely to CO₂(g) and H₂O(l) according to the following thermo-chemical equation: C₆H₁₂O₆(s)+6O₂(g)⟶6CO₂(g)+6H₂O(l); ΔH₀ = −2803kJ

Answers

Answer 1
Answer:

Final answer:

To calculate the mass of glucose needed to provide nourishment to the global population for one year, multiply the daily energy requirement by the total number of days and the global population. Convert the energy to mass using the thermo-chemical equation.

Explanation:

To calculate the mass of glucose needed to provide 1200 cal/person/day of nourishment to the global population for one year, we need to determine the total energy required for one year and then convert it to mass using the thermo-chemical equation. First, calculate the total energy required by multiplying 1200 cal/person/day by the total number of days in a year and the global population. Next, convert the energy to kilojoules. Finally, use the energy change given in the thermo-chemical equation to convert the energy to mass of glucose.

  1. Calculate the total energy required: 1200 cal/person/day x 365 days/year x 7.0 billion people.
  2. Convert energy to kilojoules: Total energy in cal x 4.184 J/cal x 10^-3 kJ/J.
  3. Convert energy to mass of glucose: Energy in kJ / energy change in kJ (ΔH₀) in the thermo-chemical equation.

The final result will give you the mass of glucose needed in kilograms.

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Arrhenius base definition

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Arrhenius base is a substance that , when dissolved in an aqueous solution , increase the concentration of hydroxide (OH) ion in the solution


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Determine the pH of a 5x10^-4 M solution of Ca(OH)2

Answers

Ca(OH)₂ ==> Ca²⁺ + 2 OH-   

Ca(OH)
₂ is strong Bases

Therefore,  the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻.

pOH = - log[ OH⁻]

pOH = - log [ 5 x 10⁻⁴ ]

pOH = 3.30

pH + pOH = 14

pH + 3.30 = 14

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Pierce conducts an experiment in which waves collide in a way that the energy increases, which means that has occurred

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Answer:

It means the waves collides and constructive interference occurred.

Explanation:

If the two waves coming from the opposite direction collide with each other, there are two way of their interference.

  • Constructive interference: An interference which results in the increase in energy. And it is when crust of a wave comes on the crust of second wave.
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Hence in experiment there will be constructive interference.

Answer:

C.

Explanation:

I took the test!

Which compound forms a saturated solution at 40 degrees C that contains 46 grams per 100 grams of water?

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The correct answer for the question that is being presented above is this one: "NH4Cl." The compound that forms a saturated solution at 40 degrees C that contains 46 grams per 100 grams of water is the NH4Cl. Ammonium chloride is an inorganic compound with a white crystalline salt that is highly soluble in water.

Describe and explain how petrol is separated from the mixture of hydrocarbons in crude oil?

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It's an exciting and interesting process but those 5 points aren't worth a decent answer. The whole process is called fractioned distillation where different temperatures are reached, transforming the crude oil in gas. After being hit by a cold source it colds becoming different hydrocarbons depending on the temperatures.

CH3COOH mc015-1.jpg CH3COO– (aq) + H+(aq)What will happen to the chemical equilibrium of the solution if CH3COONa is added?

Answers

The equilibrium will shift to the left or the backward reaction since addition of CH3COONa will add more CH3COO- ions to the solution. The formation of reactants are promoted since the reactions tends to go to a new equilibrium because of the addition.

Answer:

The equilibrium will shift to the reactants and increase the concentration of CH3COOH

Explanation:

According to Le Chatelier's principle when a system at equilibrium is subjected to a change in temperature, pressure, concentration etc then the equilibrium will shift in a direction to undo the effect of the induced change.

The given reaction is:

CH3COOH ↔ CH3COO-(aq) + H+(aq)

CH3COONa exists as ions i.e. CH3COO- and Na+. Therefore, addition of CH3COONa will introduce more CH3COO- ions into the system as a result the equilibrium will shift to the left i.e. towards the reactants and will produce more of CH3COOH