Suppose the human trait for freckles is controlled by a simple dominant and recessive relationship at one locus. Freckles, F, is the dominant allele, and a lack of freckles, f, is the recessive allele. In a college genetics class, the professor takes a tally of students who have freckles and of students with a lack of freckles. In this class of 123 students, 98 have freckles. Calculate the frequency of the dominant allele, F, and the heterozygous genotype Ff. Express the frequencies in decimal form rounded to the nearest thousandth. Assume the class is in hardy-Weinberg equilibrium for this trait.

Answers

Answer 1
Answer:

Answer:

0.549 is the frequency of the F allele.

0.495 is the frequency of the Ff genotype.

Explanation:

FF or Ff genotypes determine freckles, ff determines lack of freckels.

In this class of 123 students, 98 have freckles (and 123-98= 25 do not).

If the class is in Hardy-Weinberg equilibrium for this trait, then the genotypic frequency of the ff genotype is:

q²= 25/123

q²=0.203

q= \sqrt{0.2

q= 0.451

q is the frequency of the recessive f allele.

Given p the frequency of the dominant F allele, we know that:

p+q=1, therefore p=1-q

p=0.549 is the frequency of the F allele.

The frequency of the Ff genotype is 2pq. Therefore:

2pq=2×0.549×0.451

2pq=0.495 is the frequency of the Ff genotype.

Answer 2
Answer:

Final answer:

The frequency of the dominant allele, F, in this class is 0.55. The frequency of the heterozygous genotype, Ff, is 0.495. This is calculated using Hardy-Weinberg equilibrium and observed phenotype frequencies.

Explanation:

To start, we need to calculate the frequency of the recessive allele, f, which is easily calculated as those who do not have freckles. From a total of 123 students, 98 have freckles, leaving 25 students with no freckles, which represents individuals who are homozygous for the recessive trait (ff). As these are the only individuals we can be sure of, we take the square root of their frequency to get the frequency of the recessive allele, q. In this case, q = sqrt(25/123) = 0.45. To find the frequency of the dominant allele, p, we subtract q from 1 (because p + q = 1), so p = 1 - q = 0.55.

Next, we'll calculate the frequency of the heterozygous genotype Ff.

Using Hardy-Weinberg equilibrium, we know this is represented by 2pq. Hence, the frequency of genotype Ff would be 2 × 0.55 × 0.45 = 0.495.

This process offers an example of applying the principles of population genetics and Hardy-Weinberg equilibrium to determine the likely genotype frequencies in a given group of individuals based on observed phenotype frequencies.

Learn more about Genetic Frequencies here:

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Why does an insertion mutation usually cause more defects during protein synthesis than a point mutation?a. insertion mutations only occur during transcription.
b. insertion mutations can only be silent mutations.
c. insertion mutations can affect many amino acids in the protein.
d. insertion mutations are chromosomal mutations?

Answers

The study of cells is called cell biology. There are two types of a cell on the basis of their number and these are unicellular and multicellular.

The correct answer to the question is option C that is insertion mutations can affect many amino acids in the protein.

What is transcription?

  • The conversation or transferring of the gene from DNA to RNA is called transcription.

What is mutation?

  • The abnormality in the gene in the DNA sequence which forms a mutated protein is called a mutation.

The formation of protein is called translation. This addition of genes changes the sequence of RNA which alters the protein formation while in point mutation it changes only one amino acid.

Hence, the correct answer is option C.

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An atom of which of the following elements contains six protons and electrons?

Answers

that would be carbon

You would have an isotope of carbon called carbon-12. The 12 is called the nucleon number and indicates the total number of protons and neutrons in the nucleus.

Explain how we know organisms evolved, beginning with how complex molecules were first created. At which point must science speculate about how life began? Why is that? Do you think we will ever figure out the missing clues?

Answers

Answer:

oof dis is like a whole essay if we anwsered this

Explanation:

Answer:

Untangling the origins of organisms will require experiments at the tiniest ... as scientists are hoping to discover, the path to it cannot be so hard. ... To understand how life might begin, we first have to figure out ... Some scientists think that life originally used simpler molecules and only later evolved RNA.

Explanation:

yes

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What role does coral play in the ecosystem?

Answers

Answer: Providing shelter and spawning grounds to a wide range of ocean life, coral reefs serve an important role in the marine ecosystem. ... Another role is protection from strong ocean currents and high waves. As the name "barrier reef" implies, reefs act as a barrier protecting the shorelines.

Hope this helps !

RNA has the nitrogenous base of uracil instead ofwhich is present in DNA.
A. adenine
B. cytosine
C. thymine
D. guanine

Answers

Answer:

thymine

Explanation:

Though both RNA and DNA contain the nitrogenous bases adenine, guanine and cytosine, RNA contains the nitrogenous base uracil instead of thymine. Uracil pairs with adenine in RNA, just as thymine pairs with adenine in DNA.

answer is thymine because is DNA adenine pairs with thymine and cytosine always pairs with guanine, in RNA the only thing changed is that adenine pairs with Uracil

Many cities suffer from serious air and noise pollution—as well as endless traffic jams—because of too many cars. Some people feel that cities with extensive public transportation systems should ban passenger cars and force people to walk, bike, or use public transportation. Do you think this is a good idea? Why or why not?

Answers

Answer: I do think its a good idea cause it lessens pollution in the air we breathe in and stops us from burning fossil fuels

Explanation:

Final answer:

Banning passenger cars and promoting public transportation in cities is a good idea for reducing pollution and traffic congestion.

Explanation:

I believe that banning passenger cars and promoting the use of public transportation in cities is a good idea. This approach can help reduce air and noise pollution, alleviate traffic congestion, and improve overall quality of life. By encouraging people to walk, bike, or use public transportation, cities can create a more sustainable and livable environment for their residents.

One example of a city that has successfully implemented this approach is Copenhagen, Denmark. The city has an extensive public transportation system, including a well-connected network of bike lanes. As a result, more than 60% of residents commute by bike or public transportation. This has significantly reduced air pollution and traffic congestion in the city.

Additionally, adopting this approach can have numerous benefits, such as promoting physical activity, reducing carbon emissions, and improving public health. Overall, I believe that cities with comprehensive public transportation systems should consider implementing policies that restrict the use of passenger cars in order to create a cleaner, more sustainable urban environment.