MATHEMATICS HIGH SCHOOL

What is the true solution to 2 In 4x= 2 In 8

Answers

Answer 1
Answer: 2In4x= 2In8

ln(16x^2) = ln64

Multiply e by both sides.

16x^2 = 64

Divide both sides by 16

x^2 = 4

Take the square root of both sides.

x = 2
Answer 2
Answer:

Answer:

The answer is x=2

Step-by-step explanation:

Given function is :

2In4x= 2In8

Solving this we get,

ln16x^(2) = ln64

Now using n ln m = ln m^(n) and doing further step we get

16x^(2) =64

x^(2) =(64)/(16)

This gives : x^(2) =4

x=√(4)

x=2

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Write the number 144 as a row of prime numbers multiplied together

Graph this line using the slope and y-intercept:
y=–3x–3

Answers

Answer:

Check the attachment (image).

Step-by-step explanation:

The slope is -3, so you have to put a point on the y-intercept (where the line touches the y-axis), or -3. Then you have to put a point 3 down (so -6 on the y-axis), and 1 right (so 1 on the x-axis) since the slope is actually:
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...now you get a ruler and make a line running through those points (if on paper).

Please help as soon as you can .

Answers

Step-by-step explanation:

let's find the circumference of the semi circle. as it's a parallelogram opposite sides are equal. therefore 2 semicircles will have the same circumference

circumference of circle = 2pi r

circumference of half circle = half of circle= pi r

circumference of half circle = 22/7 × 4 ( diameter is 8 therefore radius is half of that)

circumference of half circle = 88/7

this image has 2 half circles with same radius

now find the perimeter of total figure

perimeter= 9+ 9+ 88/7 +88/7

= 18 + 176/7

= 18+ 25.14

= 43.14

to nearest tenth place = 43.1

Answer:

8+8+9+9

If 8 is the diameter then that's the answer

Prime factorization for 58, 2,800, 212, 900

Answers

The prime factorization for:
- 58 ----> 2, 29
- 2800 ----> 2^4 * 5^2 * 7
- 212 ----> 2*2*53
- 900 ----> 2*2*3*3*5*5
I hope this helped you...

HELP PLS this is my last question

Answers

Answer:

The solutions to the system of the equations are:

y=1,\:x=3

Step-by-step explanation:

Given the equations

y=(2)/(3)x-1;\:y=-x+4

solving the system of equation

\begin{bmatrix}y=(2)/(3)x-1\n y=-x+4\end{bmatrix}

Arrange equation variables for elimination

\begin{bmatrix}y-(2)/(3)x=-1\n y+x=4\end{bmatrix}

y+x=4

-

\underline{y-(2)/(3)x=-1}

(5)/(3)x=5

\begin{bmatrix}y-(2)/(3)x=-1\n (5)/(3)x=5\end{bmatrix}

solving for x

(5)/(3)x=5

5x=15

Divide both sides by 15

(5x)/(5)=(15)/(5)

x=3

\mathrm{For\:}y-(2)/(3)x=-1\mathrm{\:plug\:in\:}x=3

y-(2)/(3)\cdot \:3=-1

y-2=-1

Add 2 to both sides

y-2+2=-1+2

y=1

Therefore, the solutions to the system of the equations are:

y=1,\:x=3

Find the unknown length. Round to the nearest tenth if necessary.

Answers

Answer:

a = 7.4

Step-by-step explanation:

Since this is a right triangle, we will use the Pythagorean theorem:

c^2 = a^2 + b^2

28^2 = a^2 + 27^2

784 = a^2 + 729

55 = a^2

a = 7.4

Answer:

55 i believe

28 + 27 = 55

Ten times the quotient of 104 and 8. write as a expression

Answers

10 (104/8)
First you complete whats in the parenthesis. 104/8=13
Then multiply 13 by 10 to get 130
Expression:
10 × ( 104 ÷ 8)

Solution (if needed)
10 × 13 
130
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