(b) After Mike opens his parachute, he continues to descend, eventually reaching the ground with a speed of 4.0 m/s. Calculate the average upward force during this part of Mike's descent.
(c) At the same time Mike jumps out of the airplane, his wallet (mass of 0.3 kg) falls out of his pocket. Calculate the wallet's downward speed when it reaches the ground. For this calculation, assume that air resistance is negligible.
The average magnitude of the upward force of air resistance on Mike during his initial descent is 0 N. The average upward force during the descent after Mike opens his parachute is 1.552 N. The downward speed of the wallet when it reaches the ground is 196.196 m/s.
(a) Average magnitude of the upward force of air resistance:
To find the average magnitude of the upward force of air resistance during Mike's initial descent, we need to calculate the net force acting on him. This can be done by subtracting his weight from the gravitational force:
Net force = gravitational force - weight
Gravitational force = mass * acceleration due to gravity = 97 kg * 9.8 m/s2 = 950.6 N
Weight = mass * acceleration due to gravity = 97 kg * 9.8 m/s2 = 950.6 N
Net force = 950.6 N - 950.6 N = 0 N
Since the net force is 0 N, the average magnitude of the upward force of air resistance is also 0 N.
(b) Average upward force after opening parachute:
When Mike opens his parachute, air resistance plays a significant role in slowing him down. The average upward force can be calculated using the equation:
Average upward force = mass * acceleration
Acceleration = (final speed - initial speed) / time
Time = distance / (final speed - initial speed)
Acceleration = (4.0 m/s - 68 m/s) / (1000 m / (4.0 m/s - 68 m/s)) = 0.016 m/s2
Average upward force = 97 kg * 0.016 m/s2 = 1.552 N
(c) Speed of the wallet:
Since the wallet has negligible air resistance, we can use the equation for freefall to calculate its speed:
Final speed = initial speed + acceleration * time
Acceleration = acceleration due to gravity = 9.8 m/s2
Time = sqrt(2 * height / acceleration) = sqrt(2 * 2000 m / 9.8 m/s2) = 20.02 s
Initial speed = 0 m/s
Final speed = 0 m/s + 9.8 m/s2 * 20.02 s = 196.196 m/s
Therefore, the downward speed of the wallet when it reaches the ground is 196.196 m/s.
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The force of air resistance on Mike during his initial descent and after opening his parachute is approximately 950.6 N. Ignoring air resistance, his wallet will reach the ground at approximately 198 m/s.
The subject of this question is Physics, and it requires understanding of forces and kinematics to apply to the real world scenario of skydiving.
During the initial descent, Mike doesn't have a parachute open. So, the only forces at play initially are his weight and the force of air resistance. We know that he achieves a steady speed of 68 m/s, which means the forces are balanced (net force is zero). Since weight and air resistance counterbalance each other, we calculate the weight by multiplying mass (97 kg) by acceleration due to gravity (9.8 m/s2), which yields 950.6 N. Given the forces balance, this is also the force of air resistance and the answer to part (a).
After the parachute opens, Mike continues to descend, eventually reaching the ground with a speed of 4.0 m/s, indicating a different balance between weight and airresistance. The weight remains the same, but the air resistance (upward force) has increased and once again equals weight since there is no acceleration. Hence, the upward force is still 950.6 N.
For the wallet, we're told to ignore air resistance. So, it's a free fall scenario. We can use the equation of motion v2 = u2 + 2gs to calculate the final speed. Initial speed (u) is 0, g is 9.8 m/s2 and s (displacement) is 2000 m. Substituting these values in, we calculate a final speed of approximately 198 m/s.
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it just stop moving? If not, where does
it go?
Answer: The ice and shel are at the same temperature.
Explanation: Conduction happens when you have two objects at different temperatures touching each other, in this case, the temperature flows from the hot object to the cold one, until the equilibrium is reached (this means that both objects are at the same temperature). So, in order to conduction to happen, we need a difference in temperature and direct contact. So there are two options of the given that can be the answer: "There is no direct contact" In the sentence says that "the ice is placed on the freezer shelf", so we have direct contact between both objects. "The ice and shelf are at the same temperature" Here both objects are inside of the freezer, so we can expect that both of them are at the same temperature, hence, there is no conduction.
Answer:
the correct answer is d
Explanation:
B. Electrons are transferred from the oxygen atoms to the carbon atoms.
C. Many valence electrons are shared between the atoms.
D. A few valence electrons are shared between the atoms
Answer : The correct option is C.
Explanation :
Covalent bond : Covalent bond forms when two non-metal atom share a pair of electrons.
In the covalent bond formation of carbon dioxide, carbon and oxygen atom share four pair of electrons. The carbon atom joined by four covalent bonds to two oxygen atoms.
The valence electrons in carbon atom = 4
The valence electrons in two oxygen atom = 2(6) = 12
Therefore, these atoms are rearranged to form the bonds by the sharing of many valence electrons between the atoms.
The lewis-dot structure of carbon dioxide is shown below.
Answer:
Person above me got it correct
Explanation:
The answer is C Many valence electrons are shared between the atoms
Just confirming :)
Answer:
This new element belongs to the group 2.
Explanation:
In the periodic table, the vertical columns are called groups (or families). The elements in the same group share similar chemical and physical properties.
One of these properties is the same amount of outer valence electrons.
For example, in the group 1 the elements have 1 outer valence electron (If we assume that the element is in a neutral state which is without electrical charges).
If this new element has 2 electrons in its outer level it will belong to the group 2. The group 2 is well-known as alkaline earth metals.
For example, the magnesium (Mg) and the calcium (Ca) belong to the group 2.