The model below represents a nuclear reaction. Atom 1 is present before the reaction and Atom 2 and Atom 3 are produced after the reaction.Atom 1 = Atom 2 + Atom 3 + energy

The model most likely represents a reaction which
Select one:
a. takes place when atoms combine
b. takes place when atoms become inactive
c. does not produce energy in the sun
d. does not produce energy in nuclear power plants

Answers

Answer 1
Answer:

Answer: b: takes place when atoms become inactive

Explanation: the model described above is a nuclear fission reaction, a reasonably controlled reaction that releases energy and is employed in nuclear power plants. In these reactions one Atom is split into two lighter ones and there's a resultant release of energy in the process. The original Atom becomes depleted (inactive) as is the case with Uranium 235.

This reaction is opposed to fusion reactions that occur in nature e.g. the sun, and are basically uncontrollable — involving the combination of two atoms into one.

Answer 2
Answer: The right answer for the question that is being asked and shown above is that: "d. does not produce energy in nuclear power plants." The model most likely represents a reaction which d. does not produce energy in nuclear power plants

Related Questions

For the chemical reaction C2H6 + 137 kJ C2H4 + H2, the chemical energy of thea. reactant is greater than the chemical energy of the products. b. products is greater than the chemical energy of the reactant. c. reactant and the chemical energy of the products are equal. d. reaction is conserved.
True or false Diprotic acids lose both hydrogens at the same time
As a chemical reaction occurs, the thermometer in the container records an increase in temperature. What is true of the reaction? The reaction is endothermic because heat was taken in by the reaction. The reaction is exothermic because heat was released by the reaction. The reaction is endothermic because heat was released by the reaction. The reaction is exothermic because heat was taken in by the reaction.
A compound is formed when 171.2 g of carbon reacts with 28.8 g of hydrogen. What is the mass percent of hydrogen in the compound
In the following reaction: Ca+2 + 2Br- ---> BaBr2, which of the reactants is LEO and which is GER?

1. Calculate the amount of heat required for 25.0 grams of water tochange from 10 degrees Celsius to 30 degrees Celsius. 2. 50.0 grams of water at 100 degrees Celsius evaporated to water vapor 2 points
at 100 degrees Celsius. Calculate the amount of heat required for this
conversion.

3. A student measured 15.0 grams of ice in a beaker. The beaker was then
placed on a hot plate where it was heated uniformly for a certain amount
of time. During the melting process of the ice, the student noted that the
temperature was at 0 degree Celsius. When all the ice converted to water,
the final temperature was also at 0 degree Celsius. How much heat was
used to melt the ice?

4. If 5.0 grams of water was cooled from 50 degrees Celsius to 40
degrees Celsius, then calculate the amount of heat released by the water.

5. A certain amount of water used exactly 84.0 Joules of heat energy to
change from 25.0 degrees Celsius to 35 degrees Celsius. How many
grams of water was used?


Please help me

Answers

Answer:

Explanation:

1 )

amount of heat required = mass x specific heat x rise in temperature

= 25 x 4.2 x 20 = 2100 J .

2 )

Amount of heat required

= mass x latent heat of vaporisation

= 50 x 2260 = 113000 J  .

3 )

Amount of heat required in melting the ice

= mass x latent heat of fusion

= 15 x 336 = 5040 J

4)

heat released in cooling water

= mass x specific heat x fall in temperature

= 5 x 4.2 x 10

= 210 J

5 )

amount of heat required = mass x specific heat x rise in temperature

84 = mass x 4.2 x 10

mass = 2 grams .

What is the molality of a solution containing 125 grams of iodine (I2) and 750 grams of CCl4? A. 1.2 m. . B. 6.57 m. . C. 0.657 m. . D. 0.12 m.

Answers

The answer is C. 0.657 m.

The molality is the number of moles of solute divided by kilograms of solvent. In a solution, solute the component which is present in lesser amount while solvent is present in greater amount. Thus, I2 is solute, and CCl4 is solvent.

So, first we need to calculate moles of I2:
Atomic mass of iodine: A(I) = 126.9
Molecular mass of iodine: Mr(I2) = 2*A(I) = 2 * 126.9 = 253.8
This means there are 253.8 g of iodine in 1 mole. So, 125 g of iodine will be in how many moles?
253.8 : 1 = 125 : x         ⇒      x = 125/253.8 = 0.493 moles

Now, let's convert amount of CCl4 in kilograms (1 kg = 1000 g):
750 g = 750/1000 kg = 0.75 kg

And now, it's only left to calculate molality of the solution:
numbers of moles of solute/kilograms of solvent = 0.493 moles/0.75 kg = 0.657 m

the relative atomic mass of boron 10.2.if the element occurs in two isotopic forms,boron-10 and boron-11 ,what are their geometrical abundances?

Answers

The correct answer for the question that is being presented above is this one: 

Boron 
consists of two isotopes, boron-10 and boron-11.
Given that its relative atomic mass is 10.2

Find the abundance of each isotope.

Let y/100 = the abundance of copper-10
and (100 - y)/100 = the abundance of copper-11

10.2 = (y/100 x 10) + [(100 - y)/100 x 11] 
10.2 = 10y/100 + 1100/100 - 11y/100 
1020 = 10y + 1100 - 11y 
-80 = -y 
y = 80

Abundance of boron-10 = 10/100 = 10%

Abundance of boron-11 = 100 - 10 = 90%

Describe how you would use the information depicted in the potential energy diagram below to determine the enthalphy change of the reaction and if the reaction is endothermic or exothermic?

Answers

When the formation of a substance is negative, it means that it releases heat to the surroundings. When it releases heat to the surroundings, the reaction is exothermic. When it absorbs heat from the surroundings, the reaction is endothermic.

Hello,How can you tell if a molecular ion will have one or ore unpaired eletrons?

For example,
"Which of the following molecules is expected to have one or more unpaired electrons? Check all that apply.

O2-
F2+
N22-
O22-"
Any help would be appreciated. ...?

Answers

I believe the correct answers from the choices listed above are the first two options. The molecules O2- and F2+ are expected to have one unpaired electron. This can be determined by looking at the value of the charge. Hope this answers the question.

Final answer:

To determine unpaired electrons, look at the valence electrons in an ion's molecule, accounting for extra or absent electrons due to the ion's charge. For instance, O2- and F2+ have one unpaired electron, but N22- is not a valid ion, and O22- electrons are all paired.

Explanation:

To determine if a molecular ion will have one or more unpaired electrons, we need to look at the number of valence electrons in the molecule and take into account any extra or absent electrons due to the charge of the ion.

For example, O2- has 12 + 1 = 13 valence electrons (6 from each oxygen atom and 1 extra due to the negative charge). It requires 14 for all the electrons to be paired (2 in each oxygen's inner shell and 4 bonds or lone pairs in the outer shell), thus there is one unpaired electron in O2-.

However, in F2+, there are only 13 electrons because one electron is lost due to the positive charge. Like oxygen, fluorine also prefers to have 7 electrons in its outer shell, so there are also unpaired electrons in F2+.

N22- doesn’t exist because nitrogen normally forms triple bond and doesn’t need or want to take extra electrons, so this molecular ion is not valid.

O22- has 14 + 2 = 16 valence electrons and this total number of valence electrons is an even number, which indicates all the electrons are paired.

Learn more about Unpaired Electrons here:

brainly.com/question/29656941

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5g of a mixture of KOH and KCl with water form a solution of 250mL. We have 25ml of this solution and we mix it with 14,3mL of HCl 0,1M. What's the % of the inicial mixture?The 14,3mL of HCl are necessary to neutralize the KOH.

What are the reactions and what do I need to calculate?

Answers

we know that the number of moles HCl in 14.3mL of 0.1M HCl can be found by multiplying the volume (in L) by the concentration (in M).
(0.0143L HCl)x(0.1M HCl)=0.00143 moles HCl

Since HCl reacts with KOH in a one to one molar ratio (KOH+HCl⇒H₂O+KCl), the number of moles HCl used to neutralize KOH is the number of moles KOH. Therefore the 25mL solution had to contain 0.00143mol KOH.

To find the mass of KOH in the original mixture you have to divide the number of moles of KOH by the 0.025L to find the molarity of the KOH solution..
(0.00143mol KOH)/(0.025L)=0.0572M KOH

Since the morality does not change when you take some of the solution away, we know that the 250mL solution also had a molarity of 0.0572.  That being said you can find the number of moles the mixture had by multiplying 0.0572M KOH by 0.250L to get the number of moles of KOH.
(0.0572M KOH)x(0.250L)=0.0143mol KOH

Now you can find the mass of the KOH by multiplying it by its molar mass of 56.1g/mol.
0.0143molx56.1g/mol=0.802g KOH

Finally you can calulate the percent KOH of the original mixture by dividing the mass of the KOH by 5g.
0.802g/5g=0.1604
the original mixture was 16% KOH

I hope this helps.