MATHEMATICS HIGH SCHOOL

(2k + 3)(k - 1)A. 2k^2 + k – 3
B. 2k^2 + k + 2
C. 2k^2 – k – 3
D. 2k^2 – k + 2

Answers

Answer 1
Answer:

(2k+3)(k-1)

Use the distribute property

(2k)(k)+(2k)(-1)+(3)(k)+(3)(-1)

= 12k²-2k+3k-3

= 2k²+k-3


The answer is A


Good night

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