MATHEMATICS MIDDLE SCHOOL

Sami and her friend went to the candy store.each of them purchased a bag of jelly beans. Sandra bag weighed 1.5 pounds. Her friends bagweighed 2.5 pounds. If the candy is $4.50 per pound, how much did they spend altogether?

Answers

Answer 1

Answer:

If the candy is $4.50 per pound, Sami and her friend spent $ 18 altogether.

Solution:

Given that, Sami and her friend went to the candy store.

Each of them purchased a bag of jelly beans

Weight of sami bag = 1.5 pound

Weight of her friend bag = 2.5 pound

Cost of candy per pound = 4.50

We have to find how much did they spend altogether

Total weight of candy = Sandra bag weight + her friend bag weight

= 1.5 + 2.5 = 4 pounds

Total cost = number of pounds x 4.5 per pound

$=4 * 4.5=18$

Hence, they spent $ 18 altogether.

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b. Subtract: 3x-2/2x^2-5x-3 - 1/x-3

can anyone help me on these problems and explain how you did it please

Thank you
PLEASE HELP

Answers

a. $2 x^(2) -5x-3=2 x^(2) -6x+x-3$ (I'll explain how I split it in a bit)
$=2x(x-3)+1(x-3)$   Look for common factors between the 1st two and then the second two while trying to make sure the variables in the brackets are the same.
Now you only have to write the value in the bracket once and then join the outer factors in their own bracket so your final answer will be $(2 x^(2) +1)(x-3)$

For the first thing I did, I multiplied the first part of the equation by the last part= 2 $x^(2)$ x -3=-6 $x^(2)$ . I then proceeded to find two numbers that can be multiplied to give the result and when added will give the middle part (-5x).
Factors of -6 $x^(2)$ are: -1x and 6x, -2x and 3x, -3x and 2x, -6x and 1x. The only ones that add up -5x are -x and 6x so that was why I used them.

b. 3x-2/2x^2-5x-3 - 1/x-3
$(3x-2)/(2 x^(2) -5x-3)- (1)/(x-3) = (3x-2)/((2x+1)(x-3)) - (1)/(x-3)$
$= (1(3x-2) +1(2x+1))/((2x+1)(x-3))$
   $= (3x+2x-2+1)/((2x+1)(x-3) )$
  = $(x-1)/(2 x^(2) -5x-3)$

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