MATHEMATICS HIGH SCHOOL

Find n.
30/38= 15/n
n=______

Answers

Answer 1

Answer: multiple 38 with 15 and divide the result with 30 n = 19

Answer 2

Answer:

Answer:

Step-by-step explanation:

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Answers

Answer:

How fast are you driving, in miles per hour, if you travel 18 miles in 3/4 hour?

Step-by-step explanation:

I have just taken the quiz and its correct.

Jonas has 40 marbles. He gave 1/5 of the marbles to marvin and 3/8 of the marbles to leroy. How many marbles did each boy get?

Answers

1/5 x 40

= 8 marbles

3/8 x 40

= 15 marbles

just multiply all both fraction with 40, hence u will get

Marvin=1/5 x 40=8
Leroy=3/8 x 40=15
Jonah will have 17 marbles left.

I took notes and went back through the lesson but I can't get it. Help, please!!!

Answers

Answer:

Step-by-step explanation:

▪Picture 1. x=28

$(x)/(42) = (10 + x)/(57) \n 42(10 + x) = 57x \n 420 + 42x = 57x \n ( \: \: \: \: \: \: \: \: \: \: \: - 42x = - 42x)/( (420)/(15) = (15x)/(15) ) \n \n 28 = x$

▪Picture 2. I don't know what in trying to solve.

▪Picture 3.

•ABC = 50

•DEF = 95

•GHI = 65

•JKL = 55

▪Picture 4. I dont know how to do that

The measure of W is 134°, the measure of Y is 46°, and the measure of Z is 134°.What is the measure of X?
a 40°
b 46°
c 134°
d 90°

Answers

The angles in any quadrilateral must add up to 360 degrees.
A trapezoid is a quadrilateral, because it has four sides.

$W+X+Y+Z=360 \n \n (134)+X+(46)+(134)=360 \n \n 314+X=360 \n \n X=46$

Angle X is (b) 46 degrees.

B. 46 because the measure of all of the angles in a quadrilateral is 360. If you add 134+46+134 it equals 314, and 360-314 is 46.

Tan^2 A/1+cot^2 A + cot^2 A/1+tan^2 A=sec^2 A cosec^2 A-3

Answers

$(tan^2x)/(1+cot^2x)+(cot^2x)/(1+tan^2x)=sec^2x\ cosec^2x-3\n\nL=(tan^2x(1+tan^2x)+cot^2x(1+cot^2x))/((1+cot^2x)(1+tan^2x))=(tan^2x+tan^4x+cot^2x+cot^4x)/(1+tan^2x+cot^2x+tanxcotx)\n\n=(tan^2x+cot^2x+tan^4x+cot^4x)/(1+tan^2x+cot^2x+1)=(tan^2x+2+cot^2x+tan^4x-2+cot^4x)/(tan^2x+cot^2x+2)$

$=((tanx+cotx)^2+(tan^2x-cot^2x)^2)/((tanx+cotx)^2)=((tanx+cotx)^2)/((tanx+cotx)^2)+((tan^2x-cot^2x)^2)/((tanx+cotx)^2)\n\n=1+((tanx-cotx)^2(tanx+cotx)^2)/((tanx+cotx)^2)=1+(tanx-cotx)^2\n\n=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\n\n=\left((sinx)/(cosx)\right)^2+\left((cosx)/(sinx)\right)^2-1=(sin^2x)/(cos^2x)+(cos^2x)/(sin^2x)-1=(sin^4x+cos^4x)/(sin^2x\ cos^2x)-1$

$=((sin^2x)^2+2sin^2x\ cos^2x+(cos^2x)^2-2sin^2x\ cos^2x)/(sin^2x\ cos^2x)-1\n\n=((sin^2x+cos^2x)^2-2sin^2x\ cos^2x)/(sin^2x\ cos^2x)-1=(1^2-2sin^2x\ cos^2x)/(sin^2x\ cos^2x)-1\n\n=(1)/(sin^2x\ cos^2x)-(2sin^2x\ cos^2x)/(sin^2x\ cos^2x)-1=(1)/(sin^2x)\cdot(1)/(cos^2x)-2-1\n\n=cosec^2x\cdot sec^2x-3=sec^2x\ cosec^2x-3=R$

How many possible outcomes are there when flipping a coin 7 times?