A triangle has a base of 4 units and a height of 3 units. Mark draws the triangle again but doubles the height. How does the area of the triangle change?

Answers

Answer 1

Answer:

Answer:

It doubles the area.

Step-by-step explanation:

The formula for the area of a triangle is a = bh/2. So, if we plug in the first triangle, you get a = 6. With the second triangle, the height is being doubled. We can represent this with the equation:

4 × 3 × 2/2

Both 2s cancel each other out, leaving us with a = 12. 12/6 is 2. Therefore, doubling the height will ALWAYS double the area.

Answer 2

Answer:

Answer: The answer is B, please mark me brainliest.
Thank you.

Step-by-step explanation:

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Debbie estimated that a caterpillar was 4.5 cm long. Later, she found its actual length to be 4.8 cm. Find the percent error.

Answers

Answer:

Step-by-step explanation:

divide 4.5/4.8. you get .9375.

subtract this from 1

1-.9375

and you get 0.0625.

multiply that by 100 to get it into percent form

6.25%

6.25

4.8-4.5
0.3 divide 4.8= 0.062 x 100= 6.25

twice a number plus another number is 310. The difference between the two numbers is 55. What are the two numbers

Answers

t us assume the two numbers to be "x" and "y".
Then
2x + y = 310
And
x - y = 55
Let us take the second equation and find the value of x in relation to y.
x - y = 55
x = y + 55
Now let us put the value of x in the first equation, we get
2x + y = 310
2(y + 55) + y = 310
2y + 110 + y = 310
3y = 310 - 110
3y = 200
y = 200/3
= 66 2/3
Now putting the value of y in the second equation, we get
x - y = 55
x - (200/3) = 55
3x - 200 = 55 * 3
3x = 165 + 200
x = 365/3
= 121 2/3
So the value of x is 121 2/3 and the value of y is 66 2/3

lets say the first number is x and the second y

twice the first number is 2x plus another number (y) =310
the difference of the numbers (x-y) = 55
we have simultaneous equations here:
2x+y=310
x-y=55

to cancel the y's the signs are different so you add the equations to give
3x=365
divide it by 3 to get:
x=121 and 2/3

using the easier equation x-y=55 we know x=121 2/3
now we substitute to get 121 2/3 -y=55
take 121 2/3 from both sides to get:
-y= -66 2/3
therefore y= 66 2/3

that means x=121.6(recurring) and y= 66.6(recurring)

If someone could help me figure this out I'll love you forever

Answers

Answer:

1. Not rhombus

2. Rhombus

3. Rhombus

Step-by-step explanation:

The little lines you see represent the size. So if you see one line on all sides, its a rhombus. If you see 1 line on one side, 2 lines on two sides, and 3 on the last side, it is not a rhombus.

Look for the lines.

Sin A - 2 sin cube A
---------------------------
2 cos cube A - cos A

Answers

$(sin\alpha-2sin^3\alpha)/(2cos^3\alpha-cos\alpha)=(sin\alpha(1-2sin^2\alpha))/(cos\alpha(2cos^2\alpha-1))=(sin\alpha(1-sin^2\alpha-sin^2\alpha))/(cos\alpha(cos^2\alpha+cos^2\alpha-1))\n\n=(sin\alpha(cos^2\alpha-sin^2\alpha))/(cos\alpha(cos^2\alpha-sin^2\alpha))=(sin\alpha)/(cos\alpha)=tan\alpha\n\n\nsin^2\alpha+cos^2\alpha=1\to cos^2\alpha=1-sin^2\alpha\nsin^2\alpha+cos^2\alpha=1\to sin^2\alpha=1-cos^2\alpha\to-sin^2\alpha=cos^2\alpha-1$

What is the value of the digit 3 in the number 43

Answers

The 3 is in the ones place, so the value is 3 x 1 = 3

Find the solutions to y = (x – 1)2 for x = –3, 0, and 3. (–3, –2), (0, 1), (3, 4) (–3, –16), (0, 1), (3, 4) (–3, 16), (0, 1), (3, 4) (–3, –4), (0, –1), (3, 2)

Answers

Answer:

The pairs of ( x,y) are ( -3 ,16) , ( 0,1) and ( 3,4)

Step-by-step explanation:

y = ( x -1)²

y = x² - 2 x + 1

for x = -3

y =( -3)² - 2 × -3 + 1

= 9 +6 +1

= 16

so ( x, y) = ( -3 , 16)

for x = 0

y = 0² - 2 ×0 + 1

= 1

so ( x,y) = ( 0,1)

For x = 3

y = 3² - 2 × 3 +1

= 9 - 6 +1

= 4

( x,y) = (3 , 4)

so the pairs of ( x,y) are ( -3 ,16) , ( 0,1) and ( 3,4)

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Which of the following statements about physical fitness is TRUE?A Physical fitness is a continuous, changing state.B. Physical fitness is influenced by many factors.C. Physical fitness is individualized to each personD. all of the abovePlease select the best answer from the choices provided.Mark this and returnSave and ExitNextSubmit