What would you have to do to change 10 cubic feet into cubic inches? A. Multiply by 46,656 B. Divide by 1,728 C. Multiply by 1,728 D. Divide by 46,656
Answers
(1 foot)³ = (12 inches)³
12³ = 1,728 in³
To change 10 cubic feet into cubic inches
10 ft³ * 1728 in³/ft³ = 17,280 in³ Choice C. Multiply by 1,728
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What's the answer for this question.
If (x - 2)² = 49 , then x could be?
Rename the percent as a simplified fraction or mixed number. 1.) 30% 2.)150%
Solve by factoring by grouping 5k^2-2k-7=9
Answers
3.14 * 8^2 = 3.14*64 = 200.96 is the approximate area
If you're looking for the answer in terms of pi, 64pi is the answer.
A. 507
B. 19,548
C. 15.08
D. 579
Answers
543x36
2 Calculate 3 x 6, which is 18.
Since 18 is two-digit, we carry the first digit 1 to the next column.
3 Calculate 4 x 6, which is 24. Now add the carry digit of 1, which is 25.
Since 25 is two-digit, we carry the first digit 2 to the next column.
4 Calculate 5 x 6, which is 30. Now add the carry digit of 2, which is 32.
Since 32 is two-digit, we carry the first digit 3 to the next column.
5 Bring down the carry digit of 3.
6 Calculate 3 x 3, which is 9.
7 Calculate 4 x 3, which is 12.
Since 12 is two-digit, we carry the first digit 1 to the next column.
8 Calculate 5 x 3, which is 15. Now add the carry digit of 1, which is 16.
Since 16 is two-digit, we carry the first digit 1 to the next column.
9 Bring down the carry digit of 1.
10 Calculate 3258 + 16290, which is 19548
11 Therefore, 543 x 36 = 19548.
The answer is B.19548
Answers
This looks like it leaves SF in IV quadrant and enters LA in II quadrant. The wind will take the plane more to the east (right). Therefore the pilot must aim to the west (left) in order for the wind to push it to the intended destination of LA. The second side of the triangle should come out of LA from the II quadrant bearing 290. The length of this side is 60t (60 km/h * t = time flying). The third side of the triangle connects the first two. There for it comes out of SF at some unknown angle > 140 and connects with the 60t side. The length of this third leg is 640t. (640 km/h * t = time flying). The angle between the 540 side and the 60t side is 30. This is found because the 540 side enters LA in 2nd quadrant as 130 angle . The 60t side enters LA in 2nd quadrant as 160 angle. Using law of sin's: sin 30/640t = sin x/60t. The t's cancel and you are left with sin x = 3/64. When solving for the angle x you get x = 2.6867 degrees. Adding this to the bearing of 140, the compass bearing should be 142.6867 or 142.7 degrees. To find the value of t, you use the law of sin's to get sin 30/640t = (sin (180 - 30 - 2.6867))/540. Solving for t gives you: t = .7811. This is in hours. To convert to minutes multiply by 60 to get t = 46.87 minutes. Add this to the 2pm departure time to get 2:47 pm arrival time.
Answers
= 8 marbles
3/8 x 40
= 15 marbles
Marvin=1/5 x 40=8
Leroy=3/8 x 40=15
Jonah will have 17 marbles left.
Answers
h^2=a^2+o^2
Longest side is the same as the hypotenuse (h)
h^2=8^2+15^2
h^2=64+225
h^2=289
Square root both sides
h=17 cm