What is the volume of a rectangular object with L = 4.00 cm W = 2.00 cm H = 0.50 cm?
Answers
1) V=LWH
2)V=(4.00)(2.00)(0.50)
3)V=4cm^3
L=4
W=2
H=0.5
V=(4)(2)(0.5)
V=4cm^3
4 cubic centimeters
Related Questions
At a temperature of 280k, the gas in a cylinder has a volume of 20.0 liters.If the volume of the gas is decreased to 10.0 liters, what must the temperature be for the gas to remain at a constant pressure?
Climate gets colder closer to the poles becausea, the ice at the poles absorbs the Sun`s rays. , atmospheric and oceanic clrulation patterns move cold air toward the poles. c, heat from the poles is transferred toward the equaror. d. the Sun`s rays are less concentrated near the poles.
Convert 56 kilometers to inches
Atomic theory that states that atoms have three fundamental parts, and that electrons orbit the nucleus:
B. nuclear force
C. centrifugal force
D. centripetal force
Answers
This definition of centripetal force is a force acting towards the center of an object moving in a circular motion. Acceleration is the rate of which velocity changes over a period of time. If you pick a point on say a rotating circle and find the tangential velocity at each point it goes through, the acceleration would be towards the middle.
Answers
the phenomenon which occurs is only the transfer of electric energy into the heat energy...
the water enters through the input and then it is passed into a container having alloy coil which is also covered by conductor of heat but this conductor cannot pass electricity into water but only heat...
then water is heated over there and comes out through outlet..
Answers
The volume of a 155-gram sample of mercury is 11.397 mL if the density of mercury is 13.6 g/mL.
What is density?
It is defined as the mass-to-volume ratio. The density indicates the object's density and is represented by the symbol. The density is measured in kilograms per cubic meter.
It is given that:
The density of mercury is 13.6 g/mL.
The mass of the mercury is 155 grams.
As we know,
Volume can be defined as a three-dimensional space enclosed by an object or thing.
The density = mass/volume
13.6 = 155/volume
volume = 155/13.6
volume = 11.397 mL
Thus, the volume of a 155-gram sample of mercury is 11.397 mL if the density of mercury is 13.6 g/mL.
Learn more about the density here:
#SPJ2
Answers
Answer:
the work done on the car by the applied force is 75 J.
Explanation:
Given;
initial velocity of the car, v = 4 m/s
applied force in opposite direction, F = 5N
initial position of the car, x₀ = 5 m
final position of the car, x₁ = 20 m
displacement of the car, Δx = x₁ - x₀ = 20 m - 5m
= 15 m
The work done on the car by the applied force is calculated as follows;
W = F.Δx
W = 5 x 15
W = 75 J
Therefore, the work done on the car by the applied force is 75 J.