6. If a person pushes a cart with a force of 40N and it accelerates at 0.5 m/s2, what is the
mass of the cart?
a. 80N
b. 80 kg
C. 20 N
d. 20 kg

Answers

Answer 1
Answer:

The mass of cart pushed by a 40 Newton force moving with an acceleration of 0.5 m/s² is 80 Kg.

What is force?

In order to move a body ofmass 'm'kg with an acceleration of 'a' m/s², a force of magnitude → |F| = ma is needed to push the body in a specified direction.

Given is a cart pushed by a 40 Newton force moving with an acceleration of 0.5 m/s².

Mass of block = m Kg   [assume]

Force on cart [F] = 40 N

Acceleration of cart [a] =0.5 m/s²

From the definition of force -

|F| = ma

m = |F|/a

m = 40 / 0.5

m = 80 kg

Therefore, the mass of cart pushed by a 40 Newton force moving with an acceleration of 0.5 m/s² is 80 Kg.

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Answer 2
Answer: F=ma
40=0.5m
m=40/0.5
m=80kg
The answr is b

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A student is pushing a box across the room. To push the box three times farther, the student needs to do how much work?

Answers

Final answer:

If the force remains unchanged, pushing a box three times farther requires three times more work because work is directly proportional to distance in the work formula W = F × d.

Explanation:

The student is asking about the work required to push a box across a room. In Physics, work is defined as the product of the force applied to an object and the distance over which it is applied, assuming force and distance are in the same direction. The formula for work is W = F × d, where W is work, F is the constant force applied, and d is the distance the object moves.

Assuming the same constant force is applied to the box if a student needs to push the box three times farther, they would do three times more work. This is because work is linearly proportional to the distance if the force remains unchanged. To illustrate, if pushing the box over a certain distance requires W joules, then pushing it three times that distance requires 3W joules of work.

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Answer:

Removing some of the books reduced the mass of the box, and less force was needed to push it across the floor.

The common name for the reflection of sound waves is an?

Answers


When sound waves are reflected in the right way so as to be heard
some time after they were generated, then the phenomenon is usually
called an "echo".

Several objects were dropped from a balcony. Using the data below, determine which statements must be true regarding the rate of force of each falling object. Neglect (ignore) air resistance.Object

Mass

Diameter

Height of drop

Tennis Ball

0.06 kg

6.6 cm

5 m

Baseball

0.15 kg

74 cm

5 m

Bowling Ball

5 kg

21 cm

5 m

Golf Ball

0.04 kg

4.3 cm

5 m

Statement 1: All balls hit the ground at the same time

Statement 2: All balls hit the ground with different forces

Statement 3: The bowling ball hit the ground first and the tennis and golf ball hit the ground last

Statement 4: It is not possible to tell how much force each ball hit the ground with

Answers

Answer:

statement 2

Explanation:

All hit at the same time

a block of aluminum has a density of 2.7 g/cm. if the block is cut in half, what will be the density of each half?

Answers

2.7 is what i got to? Hope this helps have a good day

Final answer:

The density of each half of the aluminum block remains the same as the original block, 2.7 g/cm³. Density is an intrinsic property of a material and does not change when the amount of the material changes.

Explanation:

The density of a material remains constant regardless of the amount of that material. The density is an intrinsic property defined as mass divided by volume. When you cut a block of aluminum in half, you are halving both the mass and the volume. Since both are reduced by the same proportion, the ratio of mass to volume (i.e., the density) stays the same. Thus, the density of each half of the aluminum block remains 2.7 g/cm³.

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A ball is moving at 7.0 m/s and has a momentum of 100kg.m/s. What is the balls mass?

Answers

Answer:

14 kg

Explanation:

Momentum = mass × velocity

p = mv

100 kg m/s = m (7.0 m/s)

m ≈ 14 kg

The small piston in a hydraulic system has a cross-sectional area of 0.5 m2, and the large piston has an area of 3m3. What is the force exerted by the large piston if a force of 500 N is exerted on the small piston?

Answers

     Considering the fluid as ideal, the pressure will spread throughout its volume. Thus,

(F_1)/(A_1)=  (F_2)/(A_2) \n F_2= (3* 500)/(0.5)  \n \boxed {F_2=3000N}

If you notice any mistake in my english, please let me know, because my english level is still low.