Kathy is standing directly between two tall buildings which are 100 feet apart. Her eye level is 5 feet above the ground. Kathy looks up at the top of the taller building and the top of the shorter building with angles of 45 degrees and 38 degrees above the horizontal, respectively. What is the difference in height between the taller building and the shorter building, to the nearest foot?
Answers
Angle of taller building Tan 45° = opposite (height of the building)/ adjacent 50 feet (distance between Kathy and the taller building
Tan 45° = 1
Height of taller building from eye level = multiplying adjacent 50 feet * Angle (Tan 45°) 1 = 50 feet opposite
Angle of smaller building Tan 38° = 0.781
Height of smaller building from eye level = Angle * adjacent 50 feet = 39.06 feet
Difference of eye level from ground is 5 feet
Taller building height is 50 + 5
Total height of taller building is 55 feet.
Smaller building height is 39.06 + 5
Total height of smaller building is 44.06 feet
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Answers
Answer:
18
Step-by-step explanation:
Answers
a = 60
b = 11
c = ?
60^2 + 11^2 = c^2
3600 + 121 = c^2
3721 = c^2
then just square root 3721 and c^2
c = 61 feet
y > x + 1
(–3, 2)
(–1, 3)
(0, 2)
(1, 2)
(2, –1)
(2, 2)
Answers
Answer:
(1,2) and (2,2) since blue is a solid line
Step-by-step explanation:
To prove if a point satisfies the inequalities,find the point in the point that both inequalities overlap. In the picture, this is colored purple (both pink and blue/purple).
Answer:
(1,2) and (2,2) makes true
Step-by-step explanation:
y < 5x + 2
y >=1/2(x) + 1
(–3, 2)
Plug in the ordered pair (x,y) in each inequality
2 < 5(-3) + 2 -----> false
(–1, 3)
3< 5(-1) + 2 --------> false
(0, 2)
2 < 5(0) + 2 -------> false
(1, 2)
2 < 5(1) + 2 ---------> True
2 >=(1/2)1 + 1 ----------->True
(2, –1)
-1 < 5(2) + 2 ---------> True
-1>= (1/2)(2) + 1 -----------> false
(2, 2)
2 < 5(2) + 2 ---------> True
2>= (1/2)(2) + 1 -----------> True
Answers
Answer:
Jim will incur a loss of $2,400 in the 60-day period under review
Step-by-step explanation:
The question is incomplete. However, one assumption was made in attempting the question, ie, the timeframe was set at 60-days:
Jim likes to day-trade on the internet. On a good day, he averages a $1100 gain. On a bad day, he averages a $900 loss. Suppose that he has good days 25% of the time, bad days 35% of he time, and the rest of the time he breaks even, *what is Jim's balance after a 60-day period* ?
Solution
From the question, given period X = 60 days, and;
Jim's streak is as follows: 0.25X Profit : 0.35X Loss : (100 - (0.25+0.35) Even
Jim's streak = 0.25*60 : 0.35*60 : 0.4*60 = 15 + 21 + 24 (days)
15 profitable days = 15 * $1100 = $16,500
21 bad days 21*$900 = $18,900
24 even days = 24*$0 = $0
Balance after 60 days = $16500+(-$18900)+$0 = $16500-$18900 = -$2400
Final answer:
The expected daily value for Jim's day-trading hobby is -$40, meaning he should expect to lose $40 per day. Over three weeks of trading every weekday, this amounts to a total expected loss of -$600.
Explanation:
The subject of this question is expected value, a concept in probability and statistics, which essentially means the average result of a large number of trials in an experiment. In Jim's case, three possible outcomes are concerning his day-trading hobby: a good day ($1100 gain), a bad day ($900 loss), and a break-even day ($0 gain or loss).
Here's how we calculate:
- A good day: 25% * $1100 = $275
- A bad day: -35% * $900 = -$315
- A break-even day: 40% * $0 = $0
The expected value of one day of trading for Jim is thus: $275 - $315 + $0 = -$40.
If Jim trades every weekday for three weeks (that is, 15 days), we can multiply the daily expected value by 15. So, Jim should expect to lose $40 * 15 = -$600 over three weeks.
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The complete question is given below:
Jim likes to day-trade on the Internet. On a good day. he averages a $1100 gain. On a bad day, he averages a $900 loss. Suppose that he has good days 25% of the time, bad days 35% of the time, and the rest of the time he breaks even.
a. What is the expected value for one day of Jim's day-trading hobby?
b. If Jim day-trades every weekday for three weeks, how much money should he expect to win or lose?
Answers
There are 5π/3 radians in 300 degrees.
To convert degrees to radians, we can use the formula:
Radians = Degrees x (π / 180)
Given that we want to convert 300 degrees to radians, we can plug this value into the formula:
Radians = 300 x (π / 180)
Simplifying this expression, we get:
Radians = 5π/3
Therefore, there are 5π/3 radians in 300 degrees.
Learn more about radians here;
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