Find the x-intercept of the parabola of with vertex (1,20) and the y-intercept (0,16). write your answer in this form: (x1,y1),(x2,y2)

Answers

Answer 1
Answer: I assume that the parabola in this particular problem is one whose axis of symmetry is parallel to the y axis. The formula we're going to use in this case is (x-h)2=4p(y-k). We know variables h and k from the vertex (1,20) but p is not given. However, we can solve for p by substituting values x and y in the formula with the y-intercept:

(0-1)^2=4p(16-20)

Solving for p, p=-1/16.

Going back to the formula, we can finally solve for the x-intercepts. Simply fill in variables p, h and k then set y to zero:

(x-1)^2=4(-1/16)(0-20)
(x-1)^2=5
x-1=(+-)sqrt(5)
x=(+-)sqrt(5)+1

Here, we have two values of x

x=sqrt(5)+1 and
x=-sqrt(5)+1

thus, the answers are: (sqrt(5)+1,0) and (-sqrt(5)+1,0).

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If f(x)=|3x-4|+2, find f (-10)

Answers

f(x)=|3x-4|+2\n\n\nf(-10)=|3\cdot(-10)-4|+2=|-30-4|+2\n\n=|-34|+2=34+2=36
f(x)=|3x-4|+2\n \n f (-10)=|3\cdot(-10)-4|+2=|-30-4|+2=|-34|+2=36

What is 1/4 of $8.000 dollars?

Answers

8000*(1)/(4)=(8000)/(4)=\$2000

Find the correct sum of these geometric series..*a1=343, an=-1, r= -1/7

*a1=80, n=7, r= -1/2

*a1= 3, a8=384, r=2

Please help me with these problems.. :(

Answers

1)
a_(1)=343\n a_(r)=-1\nr=- (1)/(7) \na_(r)=a_(1)* q^(r-1) \n-1=343*q^(r-1)\n-1=343* -((1)/(7))^(r-1)\n-7^0=7^3*(- 7)^(-r+1)\n7^0=7^3*7^(-r+1)\nindexes: \n0=3-r+1\nn=4
S_r=a_1 (1-r^n)/(1-r)\nS_r=343* (1- (-(1)/(7) )^4)/(1- (-(1)/(7) ))\nS_r=343* (1- ((1)/(2401) ))/(1+ ((1)/(7) ))\nS_r=343* (((2400)/(2401) ))/(((8)/(7) ))\nS_r=343* (300)/(343) \nS_r=300
2)
S= a_(1)* (1- r^(2) )/(1-r)\n S=80*(1- ( -(1)/(2)) ^(2) )/(1+(1)/(2) )\nS=80* (1- (1)/(4) )/( (3)/(2) )=80* (3)/(4)* (2)/(3) =40
3) we dont know how many numbers has this sequence

Use any model you choose to find the quotient.

5 divided by 1/2

Answers

The answer is 10. I know because I did the (multiplication) division.
When dividing fractions, you're actually multiplying the first number by the reciprocal(the number you get when you switch the numerator and denominator) of the second number. Your original equation looks like this:

5÷1/2

The first thing you want to do is find the reciprocal of your second number. In 1/2, the numerator is one and the denominator is two. When you switch the numerator and denominator, you get this:

2/1

Now two is the numerator and one is the denominator. 
Next you will multiply 5 by 2/1 (2/1 simplifies to 2)

5*2=10

And there's your answer.


2x2 − 10x − 28 6x × 6 x − 7

Answers

Answer:

no real solutions

Step-by-step explanation:

If equation is...

2x^2 - 10x - 28 = 6x(6x) - 7\n2x^2 - 10x - 28 = 6x^2 - 7\n0 = 4x^2 + 10x + 21\n4x^2 + 10x + 21 = 0

= no real solutions

Is this graph a function

Answers

Answer:

To determine if a graph is a function, we need to check if each input (x-value) has a unique output (y-value). We can do this by performing the vertical line test.

Here's how you can determine if a graph is a function using the vertical line test:

1. Imagine drawing a vertical line anywhere on the graph.

2. If the vertical line intersects the graph at more than one point, then the graph is not a function.

3. However, if the vertical line intersects the graph at only one point, then the graph is a function.

So, if you have a specific graph in mind, you can visualize drawing vertical lines and see if they intersect the graph at more than one point. If they do, then the graph is not a function. If each vertical line intersects the graph at only one point, then the graph is a function.

Step-by-step explanation: