Parallel Plates Consider a very large conducting plate at potential V0 suspended a distance d above a very large grounded plane. Find the potential between the plates. The plates are large enough so that they may be considered to be infinite. This means that one can neglect fringing fields.

Answers

Answer 1

Answer:

Answer:

$V = (V_0x)/(d)$

Explanation:

Since the field lines are parallel and the electric field is uniform between two parallel plates, a test charge would experience the same force of attraction or repulsion no matter where it is located in the field,

I attached an image that could help to understand the representation of the field. The formula used to calculate it is given by,

$E= -(\Delta V)/(x)$ (1)

If we want to consider the change in Voltage with respect to the position then it would be,

$E= -(dV)/(dx)$

According to the information provided, the potential is $V_0$ and there is a distance d, therefore

$E= -(V_0)/(d)$ (2)

Taking equation (1) we can clear V, to what we have,

$(dV)/(dx) = -E$

$dV = -Edx$

Integrating,

$V= - \int Edx$

Substituting (2)

$V = -\int (V_0)/(d) dx$

$V = (V_0x)/(d)$

Where x is the height from the grounded plate.

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A proton (charge e), traveling perpendicular to a magnetic field, experiences the same force as an alpha particle (charge 2e) which is also traveling perpendicular to the same field. The ratio of their speeds, vproton/valpha is:

Answers

Explanation:

Charge on proton, q₁ = e

Charge on alpha particles, q₂ = 2e

The magnetic force is given by :

$F=qvB\ sin\theta$

Here, $\theta=90=sin(90) = 1$

For proton, $F_p=ev_pB$ ..........(1)

For alpha particle, $F_a=2ev_aB$ ..........(2)

Since, a proton (charge e), traveling perpendicular to a magnetic field, experiences the same force as an alpha particle. So,

$ev_pB=2ev_aB$

$(v_p)/(v_a)=(2)/(1)$

So, the ratio of the speed of proton to the alpha particle is 2 : 1 .Hence, this is the required solution.

Final answer:

If a proton and an alpha particle experience the same force in a magnetic field, the proton must be traveling at twice the speed of the alpha particle. This is because the force exerted by a magnetic field on a moving charge depends on the charge of the particle, the speed of the particle, and the strength of the magnetic field.

Explanation:

The force exerted by a magnetic field on a moving charge depends on the charge of the particle, the speed of the particle, and the strength of the magnetic field. Given that a proton (charge e) and alpha particle (charge 2e) experience the same force in the same magnetic field, we can create an equation to solve for their speed ratio.

The force on a particle due to a magnetic field is given by F = qvB where q is the charge, v is the speed, and B is the magnetic field. Since the force on the proton and alpha particle are the same, we can set their force equations equal to each other.

This means that e * v_proton * B = 2e * v_alpha * B. Simplifying, the ratio v_proton/v_alpha = 2.

Therefore, the proton is moving twice as fast as the alpha particle.

Learn more about Forces in Magnetic Fields here:

brainly.com/question/3160109

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What is matter? explain and give example

Answers

Matter is generally any physical substance, and it's all around us... a form of matter would be liquid, and water is a liquid.

To estimate the width of a valley, a climber starts a stopwatch as he shouts. He hears an echo from the opposite side of the valley after 1.0s. The sound travels at 340m/ s. What is the width of the valley?

Answers

$\tt w/d=(v.t)/(2)$

w = width/distance

v = velocity

t = time

input the value:

$\tt w=(340* 1)/(2)=170~m$

If you have two substances, one with a density of 2.0 g/cm3 and one with a density of 1.3 g/cm3 and you combined them, which one would float on topother and why?

Answers

Explanation:

Assuming the substances are fluids that do not mix, the lighter substance (ρ = 1.3 g/cm³) will float on top of the heavier substance (ρ = 2.0 g/cm³). This is due to Archimedes' Principle, which explains buoyancy.

Plzzz helppppp!!! I need answers A, B, C & D

Answers

Answer: the answer i for c is yes 0& 10

Explanation:

Fuel cells have been developed that can generate a large amount of energy. For example, a hydrogen fuel cell works by combining hydrogen and oxygen gas to produce water and electrical energy. If a fuel cell can generate 10.0 kilowatts of power and the current is 15.8 amps, what is the voltage of the electricity?A.
0.63 volts
B.
158volts
C.
633 volts
D.
158,000 volts
E.
5.8 volts

Answers

The voltage of the electricity will be 632.9 V. Electric power is found as the multiplication of the voltage and current. Option B is correct.