For the substituted cyclohexane compound given below, highlight the groups – by clicking on atoms – that will sterically interact with the methyl group in a 1,3-diaxial fashion.
Answers
The atoms that would sterically interact with methyl group located axially are highlighted in pink color in the attached image.
Further Explanation:
The stereoisomer of a molecule that has same chemical formula and connectivity of bond but differs in the arrangement of the atoms in space is known as conformer. The rotation about the carbon-carbon single bond can lead to the formation of conformer of a molecule.
There are four conformers of cyclohexane molecule as follows:
- Chair conformation
- Boat conformation
- Twist boat conformation
- Half chair conformation
Chair conformation is considered as the best conformation of cyclohexane. The hydrogen in blue denote the axial positions and the hydrogen in pink denote equatorial positions. (Refer to the attached image)
The stable conformation is that in which the bulky groups such as hydroxyl, methyl, and nitro group occupy the equatorial positions while the relatively small groups such as hydrogen atoms occupy axial positions. The reason is that the axially placed substituents suffer more steric repulsion and that generates strain in the molecule. The strain leads to high energy and thus less stability.
While writing the chair conformation the bulkier groups are preferentially placed at equatorial positions. The conformation that has bulky group at equatorial position is more favorable than the conformation that has bulky group at axial position. The reason for the stability of the conformation is diaxial interactions.
1,3-diaxial interaction: The 1,3-diaxial interactions occur among the axial substituent present at 1 and 3 positions.
The conformation in the problem has axial substituent hydrogen and bromine at the two positions 3 and 3’ which lead to 1,3-diaxial strain in the molecule and makes it unstable. (Refer to the attached image)
Learn more:
1. Balanced chemical equation brainly.com/question/1405182
2. Oxidation and reduction reaction: brainly.com/question/2973661
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Conformation of cyclohexane
Keywords: Cyclohexane, planar, chair conformation, axial positions, equatorial positions, steric repulsion, high energy, 1, 3-diaxial interaction, 1, 3-diaxial strain.
Final answer:
In a substituted cyclohexane, 1,3-diaxial interactions happen between groups on the same side of the ring but are two carbons apart. In this scenario, the hydrogen atoms on carbons 3 and 5 would interact with the methyl group, causing steric strain.
Explanation:
In a substituted cyclohexane compound, 1,3-diaxial interactions occur between groups that are on the same side of the ring but are two carbons apart. In this case, the question focuses on the steric interactions with the methyl group. Assuming that the methyl group is on carbon-1 of the ring, the hydrogen atoms on carbons 3 and 5 (both axial positions) on the same face of the ring would sterically interact with the methyl group in a 1,3-diaxial fashion. This steric interaction leads to steric strain, which destabilizes the compound and promotes a conformational flip to relieve this strain.
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What tendency is the standard reduction potential of an element based on?
The arrangement of particles is least ordered in a sample ofa. NaCl(aq)b. NaCl()c. NaCl(g)d. NaCl(s)
Answers
Answer:
a. spilled marbles
Explanation:
entropy is the tendency toward a state of disorder or randomness, so the spilled box of marbles has the higher entropy
Final answer:
The spilled marbles and marbles in a packed box have different states of entropy.
Explanation:
Entropy is a concept in thermodynamics that refers to the disorder or randomness of a system. In this case, the state with the higher entropy would be the spilled marbles. When marbles are neatly packed in a box, they are in a more ordered and organized state, resulting in lower entropy. However, when the marbles are spilled on the floor, they are now in a more disordered and random state, leading to higher entropy. Therefore, the answer is d. both.
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B. +1 and the same mass as a proton
C. –1 and a smaller mass than a proton
D. +1 and a smaller mass than a proton
Answers
Answers
Answer: The mass of aluminium cylinder is 4065 kg.
Explanation:
Density is defined as the ratio of mass of the object and volume of the object.
Mathematically,
We are given:
Density of aluminium =
Volume of aluminium cylinder =
Putting values in above equation, we get:
Hence, the mass of aluminium cylinder is 4065 kg.
therefore; 2700g/m^3 X 1.50m^3 = 4050g = 4.05Kg
Just use the units of density (mass/volume) and the units of what's given to figure it out :)
Answers
Answer:
SbCl5
Antimony pentachloride
Antimony pentachloride is a chemical compound with the formula SbCl5.
- wikipedia
Express your answer using three significant figures.
Answers
Answer:
-115°C is the temperature on planet X.
Explanation:
Pressure inside the space station =
1 atm = 760 mmHg
Temperature inside the space station =
Volume of the air filled in the balloon =
1 mL = 0.001 L
Atmospheric pressure on planet X =
Temperature on the planet X =
Volume of the air filled in the balloon on planet X =
Using combined gas equation :
-115°C is the temperature on planet X.
Final answer:
Using the ideal gas law, the temperature on planet X is calculated to be approximately -148.5 °C, after converting all units to standard and then adjusting the final result from Kelvin to Celsius.
Explanation:
This is a classic problem in physics that uses the ideal gas law, which states that the pressure of a gas multiplied by its volume is directly proportional to the amount of gas and the temperature. Using the provided data about the initial conditions inside the space station and the final conditions on planet X, the final temperature can be found by using the equation P1V1/T1 = P2V2/T2, where P refers to pressure, V refers to volume, and T refers to temperature.
First, we need to convert all measurements to the standard units: Pressure in atm and volume in liters. So, initially the pressure inside the space station is 761 mmHg or approximately 1 atm (since 1 atm = 760 mmHg), the volume of the balloon is 855 mL or 0.855 L, and the temperature is 27 °C or 300.15 K (since 0 °C = 273.15 K). On planet X, the pressure is given as 0.14 atm and the volume as 3.21 L.
Substituting these values into our ideal gas law equation, we can find the final temperature T2 on planet X: T2 = P2V2T1 / P1V1 = (0.14 atm * 3.21 L * 300.15 K) / (1 atm * 0.855 L) = approximately 124.68 K.
To convert this value from Kelvin to degrees Celsius, we subtract 273.15, getting approximately -148.47 °C.
Therefore, the temperature on planet X is approximately -148.5 °C, given to three significant figures.
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Answers
Answer: N (atomic number 7)
Explanation:
1) Due the electron distribution of each, taking into account Hund's rule to deal with pairing of electrons.
2) Hund's rule: each subshell orbital is occupied with single electrons of parallel spin before double occupation occurs.
That is, before any one orbital is doubly occupied, every orbital in a subshell is singly occupied with one electron, and all the electrons in singly occupied orbitals have the same spin, which means that they are unpaired.
3) Distributions:
a) C (atomic number 6) ⇒ 6 electrons:
⇒ 1s² 2s² 2p² ⇒ 1s² 2s² 2p ↑ ↑ : as per Hund's rule the two electrons on 2p are unpaired.
b) O (atomic number 8) ⇒ 8 electrons
⇒ 1s² 2s² 2p⁴ ⇒ 1s² 2s² 2p⇅ ↑ ↑: as per Hund's rule the two 2p electrons are unpaired
c) N (atomic number 7) ⇒ 7 electrons
1s² 2s² 2p³ ⇒ 1s² 2s² 2p↑ ↑ ↑: as per Hund's rule, the three 2p electrons are unpaired, so this is the answer to the question.
c) Be (atomic number 4) ⇒ 4 electrons
⇒ 1s² 2s² ⇒ none p electron.
Final answer:
Nitrogen has three unpaired electrons in its p orbital.
Explanation:
Among the given elements, nitrogen (atomic number 7) has three unpaired electrons in its p orbital.
In the electron configuration of nitrogen, it has a total of five electrons: 2 in the 1st energy level and 3 in the 2nd energy level. The p sublevel of the 2nd energy level contains three orbitals, each capable of holding 2 electrons. Therefore, the three unpaired electrons in nitrogen's p orbital are in three separate p orbitals in the 2nd energy level.
Carbon has two unpaired electrons in its p orbital, while oxygen has two unpaired electrons in its p orbital and two in its s orbital. Beryllium does not have any unpaired electrons in its p orbital.
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