How does a quadratic function differ from that of a linear or exponential

Answers

Answer 1
Answer: Hello,

A linear function is a polynomial function of degree 1
(1,2,3,4,5,6,....)
A quadratic function is a polynomial function of degree 2
(1,4,9,16,25,49,64,81,...)
A exponential function is not a polynomial function (we may imagine a infinity degree)
(1,2,4,8,16,32,64,128,256,512,1024,...)




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Round to the nearest hundredth. 7.546A. 7.546B. 7.55C. 7D. 7.5
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A bag contains 99 red marbles and 99 blue marbles. Taking two marbles out of the bag, you: • put a red marble in the bag if the two marbles you drew are the same color (both red or both blue), and • put a blue marble in the bag if the two marbles you drew are different colors. Repeat this step (reducing the number of marbles in the bag by one each time) until only one marble is left in the bag. What is the color of that marble?

Which term of the AP:3,15,27, 39,.....will be 132 more than its 54th term​

Answers

Answer:

n=65th term

Step-by-step explanation:

AP:3,15,27,39......

From the AP

a=3

a+d=15

a+2d=27

3+d=15 (1)

3+2d=27 (2)

Subtract (1) from (2)

We have,

2d-d=27-15

d=12

54th term=a+(n-1)d

=3+(54-1)12

=3+(53)12

=3+636

=639

The term is 132 more than the 54th term

132+54th term

=132+639

=771

Find the term

771=a+(n-1)d

771=3+(n-1)12

771-3=12n-12

768=12n-12

768+12=12n

780=12n

n=780/12

=65

n=12

The term which is 132 more than the 54th term is the 65th term

Nell's mortgage is $50,150 at 10 percent for 30 years. What is her monthly payment if she must pay 8.78 points per $1,000? (Points : 1) $440.32
$439
$422.95
$385.89

Answers

I actually don't know the actual computation. I used a mortgage points calculator and inputted the data given.

The monthly payment given based on its computation was $440.10. The closest answer is 440.32.

The difference in decimal point is due to the rounding off of 8.78 points to 8.8 points in the calculator.

The Length of a standard jewel case is 7cm more than its width. The area of the rectangular top of the case is 408cm. Find the length and width of the jewel Case

Answers

Answer:

The length of the case is 24 cm and its width is 17cm.

Step-by-step explanation:

The Length of a standard jewel case is 7cm more than its width.

Let the length be represented by L and the width be represented by W, this means that:

L = 7 + W

The area of the rectangular top of the case is 408cm². The area od a rectangle is given as:

A = L * W

Since L = 7 + W:

A = (7 + W) * W = 7W + W²

The area is 408 cm², hence:

408 = 7W + W²

Solving this as a quadratic equation:

=> W² + 7W - 408 = 0

W² + 24W - 17W - 408 = 0

W(W + 24) - 17(W + 24) = 0

(W - 17) (W + 24) = 0

=> W = 17cm or -24 cm

Since width cannot be negative, the width of the case is 17 cm.

Hence, the length, L, is:

L = 7 + 17 = 24cm.

The length of the case is 24 cm and its width is 17cm.

Round 0.00009893 to 1 significant figure?

Answers

The significant figure, will be 0.00010 because you would have to round the nine, and the closest number to 9 is 10.

What is the quotient (3x4 – 4x2 + 8x – 1) ÷ (x – 2)?

Answers

To find the quotient of (3x^4 – 4x^2 + 8x – 1) ÷ (x – 2), First: divide 3x^4 by x to get 3x^3, then multiply 3x^3 to x - 2 to get 3x^4 - 6x^3 and subtract 3x^4 - 6x^3 from 3x^4 – 4x^2 + 8x – 1 to get 6x^3 - 4x^2 + 8x - 1 Next: divide 6x^3 by x to get 6x^2, then multiply 6x^2 to x - 2 to get 6x^3 - 12x^2 and subtract 6x^3 - 12x^2 from 6x^3 - 4x^2 + 8x - 1 to get 8x^2 + 8x - 1 Next: divide 8x^2 by x to get 8x, then multiply 8x to x - 2 to get 8x^2 - 16x and subtract 8x^2 - 16x from 8x^2 + 8x - 1 to get 24x - 1 Finally: divide 24x by x to get 24, then multiply 24 to x - 2 to get 24x - 48 and subtract 24x - 48 from 24x - 1 to get 47. Thus, (3x^4 – 4x^2 + 8x – 1) ÷ (x – 2) = 3x^3 + 6x^2 + 8x + 24 Remainder 47

Answer:

3x^3+6x^+8x+24+47/x-2

Step-by-step explanation:

What number is 30% of 68?

Answers

30%of 68 = 30/100*68= 3*68/10=204/10=20.4

Answer:

B

Step-by-step explanation:

How many problems of each point value are on the test?