MATHEMATICS HIGH SCHOOL

Find the sum or difference. (3a – 3a^2) + (5 + 8a)A: a^2 + 11a + 5

B: –3a^2 + 11a + 5

C: 3a^2 + 11a + 5

D: –3a^2 + 11a – 5

Answers

Answer 1
Answer:

Answer: B = –3a^2 + 11a + 5

For difference, the answer is

-3a^2 -5a -5

Step-by-step explanation:

(3a – 3a^2) + (5 + 8a)

To find the sum or difference, we will open the brackets.

To look for l the sum, we add

3a – 3a^2 + 5 + 8a

Collecting like terms,

= -3a^2 +8a + 3a +5

= -3a^2 + 11a + 5

Option B is the right answer.

To look for the difference, we subtract.

(3a – 3a^2) - (5 + 8a)

Opening the brackets

3a – 3a^2 - 5 - 8a

Collecting like terms

-3a^2 + 3a -8a -5

= -3a^2 -5a -5

The options available corresponds only to what we got for the sum, so

-3a^2 + 11a + 5 is the answer
Answer 2
Answer:

Answer:  B. -3a^2 + 11a + 5

1.) Remove parentheses.

3a−3a​^2​​ +5+8a

2.) Collect Like Terms.

(3a+8a) - 3a^2+5

3.) Simplify.

11a - 3a^2+5

-3a^2 + 11a + 5

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Answers

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