Suppose you have a wallet with $5 bills, $10 bills, and $20 bills. If the probability of picking a $20 bill is 4/15, and the probability of picking a $20 bill is 4/15, and the probability of picking a $5 bill is 1/3, what is the probability of picking a $20 bill?

Answers

Answer 1

Answer: The question does not make any sense. The probability of a 20 bill has already been given.

Given:
$5 bills
$10 bills
$20 bills

probability of $20 is 4/15
probability of $5 is 1/3

numerator is the number of events
denominator is the number of outcomes

the missing probability is of the $10 bill.

4/15 + 1/3 + x = 1 or 15/15

$5 bill = 1/3 x 5/5 = 5/15

15/15 - 4/15 - 5/15 = (15-4-5)/15 = (15-9)/15 = 6/15 = 2/5

the probability of $10 is 2/5

Answer 2

Answer:

Answer:

The problem isn't copied out correctly. the first $20 should be $10

Step-by-step explanation:

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Answers

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Jonathan is making his favorite pasta dish his mom ate 2/7 of the pasta his brother ate 1/6 of the pasta how much did they eat in all.

Answers

Answer: Total part of pizza ate by both is $(19)/(42)$

Step-by-step explanation:

Since we have given that

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Answers

To figure out you would first find a common factor with would be 12. After that 1/4 would be 3/12, 1/3 would be 4/12 and 1/6 would be 2/12. Next you just add all the numbers and get 9/12 then the remainder is you answer which comes to be 3/12 or 1/4. Hope that helps:)

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Answers

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Answers

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