MATHEMATICS HIGH SCHOOL

Factor the trinomial in to 2 sets of parentheses
12a squared minus 13a minus 35

Answers

Answer 1
Answer: it can't be factored because there are no 2 numbers that when you multiply you get 35 and when you add you get 13.

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What is 38% of 65? I really need help even if u are wrong.

Answers

Answer:

24.7

Step-by-step explanation:

.38(65)

Answer:

38% of 65 is 24.7

Step-by-step explanation:

38% of 65

38 × 65 ÷ 100

2470 ÷ 100 = 24.7

Thus,38% of 65 is 24.7

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Solve i=prt if i=105, p=700 & r=0.05

Answers

assuming you're trying to find t, first you would plug in the numbers given to get 105=(700)(.05)t
next, you multiply p and r to get 105=35t
after that, you divide the 105 by 35 to get the final answer of t=3

Cual es la mitad de 1.5

Answers

\frac{1.5}2=(15)/(20)=(3)/(4)=0.75.

Green eyes.

A fence will be built to enclose a 100-m by 70-m field. It will need a post at each corner and one every 5 m. How many posts are needed?

Answers

The answer is 68.

Field had shape of rectangle since has difference in length and width. The perimeter of rectangle can be expressed as:
P = 2 × (a + b)

If:
a = 100 m
b = 70 m
Then
P = 2 × (100 m + 70 m)
P = 2 × 170 m
P = 340 m.

If posts are on every 5 m, the number of needed posts is:
340 m ÷ 5 m = 68.
Thus, 68 posts are needed for the fence.

Find the value of c such that each expression is a perfect-square trinomial.Please show steps on all thank you!
1.  x^2-16x+c
2. p^2-14p+c
3. b^2+18b+c
4. n^2-n+c

Answers

(a\pm b)^2=a^2\pm2ab+b^2\n\n1.\ x^2-16x+c=x^2-2x\cdot8+c\to c=8^2=64\n\nx^2-16x+64=x^2-2x\cdot8+8^2=(x-8)^2\n\n\n2.\ p^2-14p+c=p^2-2p\cdot7+c\to c=7^2=49\n\np^2-14p+49=p^2-2p\cdot7+7^2=(p-7)^2


3.\ b^2+18b+c=b^2+2b\cdot9+c\to c=9^2=81\n\nb^2+18b+81=b^2+2b\cdot9+9^2=(b+9)^2\n\n\n4.\ n^2-n+c=n^2-2n\cdot(1)/(2)\to c=((1)/(2))^2=(1)/(4)\n\nn^2-n+(1)/(4)=n^2-2n\cdot(1)/(2)+((1)/(2))^2=(n-(1)/(2))^2

Use cramers rule to solve 4x+3y=4 -3x-y=7 show your work

Answers

\left\{\begin{array}{ccc}4x+3y=4\n-3x-y=7\end{array}\right\n\nD= \left|\begin{array}{ccc}4&3\n-3&-1\end{array}\right|=(4)(-1)-(-3)(3)=-4+9=5\n\nD_x=\left|\begin{array}{ccc}4&3\n7&-1\end{array}\right|=(4)(-1)-(7)(3)=-4-21=-25\n\nD_y=\left|\begin{array}{ccc}4&4\n-3&7\end{array}\right|=(4)(7)-(-3)(4)=28+12=40\n\nx=(D_x)/(D)\Rightarrow x=(-25)/(5)=-5\n\ny=(D_y)/(D)\Rightarrow y=(40)/(5)=8
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