Which pair of nuclei can undergo a fusion reaction?a) uranium-238 and lead-208
b) hydrogen-2 and hydrogen-3
c) zinc-64 and calcium-44 d) potassium-40 and cadmium-113

Answers

Answer 1
Answer: The correct answer is B. Fusion only happens between small atoms. Thus, hydrogen-2 and hydrogen-3 can undergo fusion. Fusion reaction happens when two or more nuclei combine or collide to form an element with a higher atomic number. In this process, some of the matter of the fusing nuclei is converted to energy.

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3.50 L of 0.200 M hydrochloric acid is prepared using 12.0 M HCl(aq) stock solution to which water is added. What volume of the stock solution
is required?

a. 7.00 mL
b. 8.40 mL
c. 17.1 mL
d. 58.3 mL

Answers

Answer:

Explanation:

To determine the volume of the stock solution required to prepare 3.50 L of 0.200 M hydro chloric acid, we can use the formula:

M1V1 = M2V2

where:

M1 = concentration of the stock solution

V1 = volume of the stock solution

M2 = desired concentration of the diluted solution

V2 = desired volume of the diluted solution

Let's substitute the given values into the formula:

M1 = 12.0 M

V1 = ?

M2 = 0.200 M

V2 = 3.50 L

Now we can solve for V1:

12.0 M x V1 = 0.200 M x 3.50 L

V1 = (0.200 M x 3.50 L) / 12.0 M

V1 = 0.0583 L

To convert the volume from liters to milliliters, we multiply by 1000:

V1 = 0.0583 L x 1000 mL/L

V1 = 58.3 mL

Therefore, the volume of the stock solution required is 58.3 mL.

So, the correct answer is d. 58.3 mL.

To determine the volume of the stock solution required, we can use the formula:

Molarity1 x Volume1 = Molarity2 x Volume2

Where Molarity1 and Volume1 represent the initial concentration and volume, and Molarity2 and Volume2 represent the final concentration and volume.

Given:

Molarity1 = 12.0 M

Volume1 = ?

Molarity2 = 0.200 M

Volume2 = 3.50 L

Plugging in the values into the formula, we have:

12.0 M x Volume1 = 0.200 M x 3.50 L

Simplifying the equation, we can solve for Volume1:

Volume1 = (0.200 M x 3.50 L) / 12.0 M

Volume1 ≈ 0.0583 L

To convert this to milliliters, we multiply by 1000:

Volume1 ≈ 58.3 mL

Therefore, the volume of the stock solution required is approximately 58.3 mL.

The closest answer option is d. 58.3 mL.

I hope this explanation helps! Let me know if you have any further questions.

Which type of pollution includes CFCs and smog?

Answers

Air pollution exist in two forms namely ozone and particle pollution. CFCs and smog are under the ozone form of pollution. Ozone type of pollution is mostly formed by reaction between the sunlight and the vapors that are emitted due to human activities. 

The is Answer is air

approximately how many grams of sodium chloride (NaCl) are required to prepare 500. mL of 3.00 M solution

Answers

First convert mL to L:
(500. mL)/(1000L) = .500L

Then convert molarity to moles:
(3.00M)(.500L) = 1.5mol NaCl

Then convert moles of NaCl to grams of NaCl by multiplying it by its molar mass:
(1.5mol NaCl)(58.44g/mol NaCl) = 87.66g NaCl are needed

Which of the following is true of coral?a.
It is located in deep sea regions.
b.
It supports few species.
c.
It is a large and complex organism.
d.
It is composed of thousands of individuals.

Answers

Coral is found close to shorelines and it can house many different types of organisms. The structures formed by colonies of coral are called reefs, the best example being the Great Barrier Reef in Australia. Coral is actually composed of the skeletons of dead coral. The coral excrete calcium carbonate, resulting in a hard structure which other organisms occupy. The answer is D.

I know for a fact that the answer to this question is d; i just took the test & got it right. It's also the most logical response. Hope i helped!

Magnesium is an alkaline earth metal with an atomic number of 12. It’s in the third row in the periodic table. Which expression shows one way to find the number of valence electrons in one atom of magnesium?

Answers

Answer:

group # = # valence electrons

group 2= 2 valence electrons

Explanation:

Mg is in group #2 and subsequently has 2 valence electrons (electrons on the outermost shell)

The recipe for pumpkin pie calls for 3 tablespoons of flour and 1.5 cups of sugar for each pie. Which of the following conversion factors would be used to find out how many pies could be made from 7.5 cups of sugar.

Answers

Answer:

5 pumpkin pies could be made with 7.5 cups of sugar.

Explanation:

The conversion factor to solve the problem is:

7.5 cups of sugar*(1 pie)/(1.5 cups of sugar) = 5 pies